Problem 72
Question
Find the domain of each function. $$ f(x)=\sqrt{x^{2}-5 x-24} $$
Step-by-Step Solution
Verified Answer
The domain of the function \(f(x) = \sqrt{x^{2}-5x-24}\) is \(-3 \leq x < 8\) and \(8 \leq x < \infty\).
1Step 1: Write down the inequality
Since the values inside the square root must be greater than or equal to 0, an inequality can be written as follows: \(x^{2}-5x-24 \geq 0\)
2Step 2: Factorize the quadratic expression
The next step involves factorizing the quadratic expression so it can be solved for x. This will give two numbers p and q such that \(p*q = -24\) and \(p + q = -5\). In this case, factorizing the expression gives: \((x-8)(x+3) \geq 0\).
3Step 3: Solve the inequality
To solve the inequality \((x-8)(x+3) \geq 0\), it's important to consider where the expression is positive, negative or zero. This happens when \(x-8 = 0\) or \(x+3 = 0\). Solving for x gives two possible values: \(x = 8\) and \(x = -3\). So, the intervals where the inequality could be positive are: \(-\infty \leq x < -3\), \(-3 \leq x < 8\) and \(8 \leq x < \infty\). By analyzing the signs, only \(-3 \leq x < 8\) and \(8 \leq x < \infty\) are true.
Key Concepts
Inequality SolvingQuadratic FactorizationSquare Root FunctionInterval Notation
Inequality Solving
When you're tasked with solving inequalities, your goal is to determine where a given expression holds true. In this case, the expression is inside a square root, which means it must be non-negative. To achieve this, first write an inequality:
- The basic requirement is for the expression under the square root to be greater than or equal to zero: \( x^2 - 5x - 24 \geq 0 \).
- This ensures that the square root value is real.
Quadratic Factorization
Factorizing quadratics is crucial in simplifying expressions, making it easier to solve inequalities. In the original problem, the quadratic expression is given by:
- You need to factorize: \( x^2 - 5x - 24 \).
- Factorization involves writing the expression as a product of two binomials: \( (x - 8)(x + 3) \).
- This is derived by finding values of \( p \) and \( q \) such that \( p \times q = -24 \) (the constant term) and \( p + q = -5 \) (the coefficient of \( x \)).
Square Root Function
A square root function is fundamentally about determining the non-negative part of a value. Therefore, it can only work with non-negative inputs. For functions of the form \( f(x) = \sqrt{something} \):
- The 'something' must be greater than or equal to zero, producing real-number solutions only for non-negative inputs.
- The range of the square root function, like \( f(x) = \sqrt{x^2 - 5x - 24} \), is dependent on the domain of the expression inside the root.
Interval Notation
Interval notation is a concise method to express a range of values. It is necessary to denote the domain of functions. In the process of solving the inequality:
- Use bracket symbols; square brackets \([ ]\) mean the endpoint is included, while parentheses \(( )\) mean it is not.
- For the expression \( \sqrt{x^2 - 5x - 24} \geq 0 \), the intervals were determined as \([-3, 8) \cup [8, \infty)\).
- This notation clearly indicates the regions where the function is valid.
Other exercises in this chapter
Problem 71
Which one of the following is true? a. The equation of the circle whose center is at the origin with radius 16 is \(x^{2}+y^{2}=16\) b. The graph of \((x-3)^{2}
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Determine whether each function is even, odd, or neither. $$f(x)=x \sqrt{1-x^{2}}$$
View solution Problem 72
If the equations of two functions are given, explain how to obtain the quotient function and its domain.
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Show that the points \(A(1,1+d), B(3,3+d),\) and \(C(6,6+d)\) are collinear (lie along a straight line) by showing that the distance from \(A\) to \(B\) plus th
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