Problem 72
Question
Find each quotient. $$\frac{-12 a b c^{2}}{12 b c}$$
Step-by-Step Solution
Verified Answer
-ac
1Step 1: Simplify the Fractions
Start by writing the fraction given in the problem: \( \frac{-12abc^{2}}{12bc} \). To simplify this fraction, we'll need to divide both the numerator and the denominator by their greatest common factor.
2Step 2: Cancel Common Factors
Identify the common factors in the numerator and the denominator. Both the numerator \(-12abc^{2}\) and the denominator \(12bc\) have the terms \(12\), \(b\), and one \(c\) in common. We can cancel these terms to simplify the fraction.
3Step 3: Simplify the Resulting Expression
After canceling the common terms, we are left with \( \frac{-a c}{1} \). Any fraction over 1 is just the numerator itself, so the expression simplifies to \(-ac\).
4Step 4: Finalize the Solution
Conclude that the simplified form of the quotient is \(-ac\). This is the final answer.
Key Concepts
Understanding the Greatest Common Factor (GCF)Numerators and Denominators in FractionsCanceling Common FactorsDecoding Algebraic Expressions
Understanding the Greatest Common Factor (GCF)
The Greatest Common Factor (GCF) is the largest factor that divides two numbers or algebraic terms without leaving a remainder. It allows us to simplify algebraic expressions by removing redundant elements. For instance, when looking at the fraction \( \frac{-12abc^2}{12bc} \), both the numerator and denominator share common factors. Here, the GCF is the number 12, along with the algebraic terms \( b \) and one \( c \). This means we can effectively divide the entire fraction by \( 12bc \), thereby simplifying it. Finding the GCF is crucial as it aids in reducing algebraic fractions to their simplest form, making computation and understanding much more manageable.To identify the GCF:
- List down the factors of each term separately.
- Find the common factors between these terms.
- Select the largest factor that is common among them.
Numerators and Denominators in Fractions
In any fraction, the numerator is the term or number found above the division line, while the denominator is below. The fraction \( \frac{-12abc^2}{12bc} \) has a numerator of \(-12abc^2\) and a denominator of \(12bc\). These two parts represent how many parts of a whole are being considered (numerator) and the total number of parts (denominator).Breaking it down:
- Numerator: In our exercise, \(-12abc^2\), which includes the variable terms \(a\), \(b\), \(c^2\), and the number \(-12\).
- Denominator: In our case, \(12bc\), comprising the variables \(b\), \(c\), and the factor 12.
Canceling Common Factors
Canceling common factors is a process where you eliminate the same elements from both the numerator and the denominator. It's a key step in simplifying algebraic fractions because it reduces complexity. For example, in \( \frac{-12abc^2}{12bc} \), the terms \( 12 \), \( b \), and \( c \) are present in both the numerator and denominator. By canceling these, you simplify the expression significantly.Here's how you do it:
- Divide the numerator and the denominator by their common terms.
- Remove or cancel these terms entirely to simplify the fraction, leaving only non-canceled components.
Decoding Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and arithmetic operations such as addition, subtraction, multiplication, and division. They're used to represent relationships and expressions in algebraic language. For instance, \(-12abc^2\) is an algebraic expression, representing the product of \(-12\), \(a\), \(b\), and \(c^2\).Key aspects of algebraic expressions:
- Use of variables to denote unknown or changeable values.
- Operations between these variables and numbers.
- They can form equations which are equalities involving expressions.
Other exercises in this chapter
Problem 72
Solve each of the equations. $$-6 x=2 x^{2}$$
View solution Problem 72
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(3 x-2)^{3}$$
View solution Problem 73
Explain how you would solve the equation \(3(x-1)\) \((x+2)=0\) and also how you would solve the equation \(x(x-1)(x+2)=0\).
View solution Problem 73
Should help you pull together all of the factoring techniques of this chapter. Factor completely each polynomial, and indicate any that are not factorable using
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