Problem 72
Question
Factor using the \(A C\) method. $$ 8 x_{2}+10 x-25 $$
Step-by-Step Solution
Verified Answer
The expression factors to \((4x - 5)(2x + 5)\).
1Step 1: Identify Coefficients
The given quadratic expression is \(ax^2 + bx + c\). Here, \(a = 8\), \(b = 10\), and \(c = -25\).
2Step 2: Calculate the Product \(ac\)
Multiply \(a\) and \(c\): \(ac = 8 \times (-25) = -200\).
3Step 3: Find Two Numbers that Multiply to \(ac\) and Add to \(b\)
We need to find two numbers whose product is \(-200\) and sum is \(10\). These numbers are \(20\) and \(-10\).
4Step 4: Rewrite the Middle Term
Rewrite the middle term \(10x\) using the numbers found: \(8x^2 + 20x - 10x - 25\).
5Step 5: Factor by Grouping
Group the terms: \((8x^2 + 20x) + (-10x - 25)\). Factor out the greatest common factor from each group: \(4x(2x + 5) - 5(2x + 5)\).
6Step 6: Factor out the Common Binomial
Factor out the common binomial \((2x + 5)\): \((4x - 5)(2x + 5)\).
Key Concepts
AC methodquadratic expressionsfactoring by grouping
AC method
The AC method, also known as the "factor by grouping method," is a technique used in factoring quadratic equations. It's especially helpful when the quadratic coefficient, denoted as \(a\), isn't equal to 1. Quadratics follow the form \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants.
To use the AC method effectively:
To use the AC method effectively:
- Multiply \(a\) and \(c\) to find the product, labeled as \(ac\).
- Identify two numbers that multiply to \(ac\) and add up to the coefficient \(b\).
- Break the middle term, \(bx\), using these two numbers.
quadratic expressions
Quadratic expressions are polynomial expressions of degree two. Presented in the format \(ax^2 + bx + c\), these expressions are foundational in algebra. They include terms with variables raised to the square, linear, and constant terms.
When dealing with quadratic expressions, the goal is often to factor them completely. Factoring transforms the expression into an equivalent product of binomials or a simpler polynomial form. This process is essential for solving quadratic equations and understanding their roots. By factoring, one can easily find the values of \(x\) that make the equation equal to zero. Finding these solutions will be simplified with techniques like the AC method and factoring by grouping.
When dealing with quadratic expressions, the goal is often to factor them completely. Factoring transforms the expression into an equivalent product of binomials or a simpler polynomial form. This process is essential for solving quadratic equations and understanding their roots. By factoring, one can easily find the values of \(x\) that make the equation equal to zero. Finding these solutions will be simplified with techniques like the AC method and factoring by grouping.
factoring by grouping
Factoring by grouping is a crucial step derived from the AC method that allows you to organize and factor expressions easily. After identifying numbers that multiply to the product \(ac\) and sum to \(b\), you split the middle term to start factoring by grouping.
You then form two groups from the quadratic expression:
You then form two groups from the quadratic expression:
- The first group consists of terms combined from the original expression. Usually, it includes the term with the highest degree.
- The second group is assembled similarly from the remaining terms
Other exercises in this chapter
Problem 72
Solve. $$ -3 x(x+8)=0 $$
View solution Problem 72
Write out your own list of steps for factoring a trinomial of the form \(x_{2}+b x+c\) and share your steps on the discussion board.
View solution Problem 73
Solve. $$ 6(x+1)(x-1)=0 $$
View solution Problem 73
The sides of a square measure \(x+3\) units. If the area is 25 square units, then find \(x\).
View solution