Problem 72
Question
Construct a polynomial function with the given zeros. $$ x=-2,-1,3 $$
Step-by-Step Solution
Verified Answer
The polynomial function with the given zeros \(x = -2, -1, 3\) is \(f(x) = (x + 2)(x + 1)(x - 3)\).
1Step 1: Identify the Zeros
The polynomial has zeros at \(x = -2, -1, 3\). These zeros will be used to construct the factors of the polynomial function.
2Step 2: Construct Factors from Zeros
The standard factor corresponding to a zero \(x_i\) is \((x - x_i)\). So the factors corresponding to the zeros at \(x = -2, -1, 3\) will be \((x + 2)\), \((x + 1)\), and \((x - 3)\), respectively.
3Step 3: Combine Factors into Polynomial
A polynomial's standard form is a sum of terms, each of which consists of a coefficient and one or more variables raised to a nonnegative integer exponent. The factors can be combined by multiplication to form a polynomial: \(f(x) = (x + 2)(x + 1)(x - 3)\).
Key Concepts
Zeros of a PolynomialFactorizationAlgebraic Expressions
Zeros of a Polynomial
The zeros of a polynomial are crucial because they are the points where the polynomial evaluates to zero. In other words, if we plug a zero into the polynomial, the result is zero. These zeros are also known as roots or solutions of the polynomial equation. For example, if we have a polynomial function \(f(x)\) with zeros at \(x = -2, -1,\) and \(3\), it means:
- \(f(-2) = 0\)
- \(f(-1) = 0\)
- \(f(3) = 0\)
Factorization
Factorization involves breaking down a polynomial into simpler components called factors, which when multiplied together give back the original polynomial. For polynomials, factors are derived from algebraic expressions that correspond to the zeros of the polynomial. Here is how it works:Suppose we have zeros \(x = -2, -1,\) and \(3\). The factors become:
- \(x + 2\) for the zero \(x = -2\)
- \(x + 1\) for the zero \(x = -1\)
- \(x - 3\) for the zero \(x = 3\)
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations like addition, subtraction, multiplication, and division. In the realm of polynomials, these expressions take on a special character, allowing us to represent and solve complex equations. Each factor of a polynomial is in itself an algebraic expression.When constructing a polynomial from its zeros, we deal with simple expressions like \((x - a)\), where \(a\) is a zero. For the polynomial with zeros \(-2, -1,\) and \(3\):
- \((x + 2)\), \((x + 1)\), and \((x - 3)\) are the basic algebraic expressions formed
- Each expression corresponds to subtracting a zero of the polynomial from \(x\).
Other exercises in this chapter
Problem 72
Divide using either long division or synthetic division. $$ \left(x^{3}+4 x^{2}-x-4\right) \div(x+4) $$
View solution Problem 72
Find the inverse of each function. $$ y=\log _{a}(x-b) $$
View solution Problem 73
Solve each equation. $$ 25^{2 x+1}=144 $$
View solution Problem 73
Write each logarithmic expression as a single logarithm. \(\cdot \frac{1}{4} \log _{3} 2+\frac{1}{4} \log _{3} x\)
View solution