Problem 72
Question
Between 2000 and \(2016,\) the estimated population of metro Chicago, Illinois, grew from 9,098,316 to \(9,512,999 .\) What was the percent increase to the nearest tenth?
Step-by-Step Solution
Verified Answer
The percent increase in population is approximately 4.6%.
1Step 1 - Identify Initial and Final Population
The initial population in 2000 is 9,098,316. The final population in 2016 is 9,512,999.
2Step 2 - Calculate the Change in Population
Subtract the initial population from the final population: \[ \text{Change in Population} = 9,512,999 - 9,098,316 = 414,683 \]
3Step 3 - Determine the Relative Increase
Divide the change in population by the initial population to get the relative increase: \[ \text{Relative Increase} = \frac{414,683}{9,098,316} \approx 0.0456 \]
4Step 4 - Convert to Percent
Multiply the relative increase by 100 to get the percent increase: \[ \text{Percent Increase} = 0.0456 \times 100 = 4.56 \% \]
5Step 5 - Round to the Nearest Tenth
Round 4.56% to the nearest tenth: \[ \text{Rounded Percent Increase} \approx 4.6 \% \]
Key Concepts
population changerelative increasepercent increase
population change
Population change refers to the variation in the number of individuals in a population over a specific period. It's a key metric for understanding demographics and planning for resources. To calculate the population change, we subtract the initial population from the final population.
For example, in the exercise, the population of metro Chicago increased from 9,098,316 in 2000 to 9,512,999 in 2016. This means the change in population is:
\[ \text{Change in Population} = 9,512,999 - 9,098,316 = 414,683 \baş\]
This value reflects the growth in the population over the 16-year period.
For example, in the exercise, the population of metro Chicago increased from 9,098,316 in 2000 to 9,512,999 in 2016. This means the change in population is:
\[ \text{Change in Population} = 9,512,999 - 9,098,316 = 414,683 \baş\]
This value reflects the growth in the population over the 16-year period.
relative increase
Relative increase gives an idea of how significant the change in population is in relation to the initial population. It offers a better perspective than the absolute change alone, as it accounts for the size of the initial population.
To calculate the relative increase, we divide the change in population by the initial population:
\[ \text{Relative Increase} = \frac{414,683}{9,098,316} \baş\]
This equals approximately 0.0456. The result tells us that the population increased by 4.56% relative to its size in the year 2000.
To calculate the relative increase, we divide the change in population by the initial population:
\[ \text{Relative Increase} = \frac{414,683}{9,098,316} \baş\]
This equals approximately 0.0456. The result tells us that the population increased by 4.56% relative to its size in the year 2000.
percent increase
Percent increase translates the relative increase into a percentage, making it easier to understand and communicate.
The formula for calculating the percent increase is: \[ \text{Percent Increase} = \text{Relative Increase} \times 100 \baş\]
In the exercise, we found the relative increase to be 0.0456. To find the percent increase, we multiply this by 100:
\[ \text{Percent Increase} = 0.0456 \times 100 = 4.56 \baş\]
For more clarity, we often round the percent increase to the nearest tenth, giving us 4.56% rounded to approximately 4.6%.
The formula for calculating the percent increase is: \[ \text{Percent Increase} = \text{Relative Increase} \times 100 \baş\]
In the exercise, we found the relative increase to be 0.0456. To find the percent increase, we multiply this by 100:
\[ \text{Percent Increase} = 0.0456 \times 100 = 4.56 \baş\]
For more clarity, we often round the percent increase to the nearest tenth, giving us 4.56% rounded to approximately 4.6%.
Other exercises in this chapter
Problem 71
Give, in interval notation, the unknown numbers in each description. One third of a number is added to 6 , giving a result of at least 3 .
View solution Problem 71
Solve each equation, and check the solution. \(0.006 x-0.02 x+0.03=0.008 x+0.25\)
View solution Problem 72
Give, in interval notation, the unknown numbers in each description. Three times a number, minus \(5,\) is no more than 7 .
View solution Problem 72
Solve each equation, and check the solution. \(0.05 x-0.1 x+0.6=0.04 x+2.22\)
View solution