Problem 72
Question
Begin by graphing the square root function, \(f(x)-\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$ h(x)--\sqrt{x+1} $$
Step-by-Step Solution
Verified Answer
The graph of the function \( h(x) = \sqrt{x + 1} \) is the graph of the square root function \( f(x) = \sqrt{x} \) shifted 1 unit to the left.
1Step 1: Understand The Square Root Function
The square root function, \( f(x) = \sqrt{x} \), is only defined for \( x \geq 0 \), and it resembles half of a sideways parabola. The point (0,0) is the vertex of the parabola.
2Step 2: Identify The Transformation
In the given function \( h(x) = \sqrt{x + 1} \), the transformation is \( x + 1 \). This is a horizontal shift. Since \( + 1 \) is inside the square root function, this implies a leftward shift of the graph by 1 unit.
3Step 3: Plot The Transformed Function
Start by plotting the square root function \( f(x) = \sqrt{x} \), then shift every point in the graph 1 unit to the left to graph \( h(x) = \sqrt{x + 1} \). As a result, (0,0) moves to (-1,0), and this becomes the vertex of the transformed function.
Key Concepts
Understanding the Square Root FunctionInsight into Horizontal ShiftsTechniques for Function Graphing
Understanding the Square Root Function
The square root function, denoted as \( f(x) = \sqrt{x} \), is fundamental in mathematics for various calculations and graphing techniques. This function is only defined for non-negative values of \( x \) (i.e., \( x \geq 0 \)), reflecting its domain limitation due to the properties of square roots.
Think of the graph of \( f(x) = \sqrt{x} \) as half of a parabola lying on its side, with its opening extending to the right. Its "vertex", which is the starting point of the graph, is located at the origin \((0, 0)\).
Think of the graph of \( f(x) = \sqrt{x} \) as half of a parabola lying on its side, with its opening extending to the right. Its "vertex", which is the starting point of the graph, is located at the origin \((0, 0)\).
- Notice that as \( x \) increases, \( \sqrt{x} \) increases as well, but at a decreasing rate, indicating a curve that flattens as \( x \) grows.
- Understanding this basic shape and behavior of the square root function is critical as it forms the foundational graph before any transformations.
Insight into Horizontal Shifts
A horizontal shift in graphing involves moving the entire graph of a function left or right on the coordinate plane. When analyzing transformations within a function, such as \( h(x) = \sqrt{x + 1} \), the term \( x + 1 \) indicates a horizontal shift.
But how does this work?
But how does this work?
- The expression \( x + 1 \) within the function means each x-value of the original function \( \sqrt{x} \) is effectively increased by 1. However, visually, this shift is counterintuitive, moving the graph to the left.
- Generally, \( x+c \) inside a function shifts the graph to the left by \( c \) units, while \( x-c \) shifts it to the right.
Techniques for Function Graphing
Graphing functions often involves understanding and measuring transformations applied to basic functions like the square root function.
When graphing a transformed function such as \( h(x) = \sqrt{x + 1} \), it is essential to follow a step-by-step method:
When graphing a transformed function such as \( h(x) = \sqrt{x + 1} \), it is essential to follow a step-by-step method:
- First, accurately sketch the basic graph you're starting with, in this case, \( f(x) = \sqrt{x} \).
- Next, apply the transformation, which here is a horizontal left shift by 1 unit.
- This means taking each point on the original graph and moving it leftward, ensuring consistent spacing and accuracy, especially for the graph's new vertex moving to \((-1,0)\).
Other exercises in this chapter
Problem 71
Use intercepts to graph each equation. \(8 x-2 y+12-0\)
View solution Problem 72
What is the horizontal line test and what does it indicate?
View solution Problem 72
Use intercepts to graph each equation. \(6 x-3 y+15-0\)
View solution Problem 73
Describe how to use the graph of a one-to-one function to draw the graph of its inverse function.
View solution