Problem 71
Question
Write the given equation either in the form \((y-k)^{2}=a(x-h)\) or in the form \((x-h)^{2}=a(y-k)\). $$ x^{2}-3 x+4=2 y $$
Step-by-Step Solution
Verified Answer
The equation in parabolic form is \((x-\frac{3}{2})^{2}=2(y-\frac{7}{8})\).
1Step 1: Examine the Equation Structure
The given equation is \(x^{2}-3x+4=2y\). This equation contains an \(x^2\) term on the left side, which suggests it might fit the form \((x-h)^{2}=a(y-k)\), which is the standard form for a parabola opening either upwards or downwards.
2Step 2: Rearrange the Equation
Rearrange the equation to isolate the \(y\) terms on one side. We have:\[ 2y = x^2 - 3x + 4 \]Now, divide through by 2 to express \(y\) in terms of the other variables:\[ y = \frac{1}{2}(x^2 - 3x + 4) \]
3Step 3: Completing the Square
To convert the quadratic equation \(x^2 - 3x + 4\) into a perfect square form, we complete the square:1. Take the coefficient of \(x\), which is -3, halve it to get \(-\frac{3}{2}\), and square it to get \(\left(-\frac{3}{2}\right)^2 = \frac{9}{4}\).2. Rewrite the quadratic expression as:\[ x^2 - 3x + \frac{9}{4} + 4 - \frac{9}{4} \]3. Combine the constant terms:\[ x^2 - 3x + \frac{9}{4} + \frac{16}{4} - \frac{9}{4} = \left(x - \frac{3}{2}\right)^2 + \frac{7}{4} \]
4Step 4: Form the Equation in Parabolic Form
Now substitute back into the equation for \(y\):\[ y = \frac{1}{2}\left(\left(x - \frac{3}{2}\right)^2 + \frac{7}{4}\right) \]Distribute the \(\frac{1}{2}\):\[ y = \frac{1}{2}\left(x - \frac{3}{2}\right)^2 + \frac{7}{8} \]
5Step 5: Write in Standard Parabolic Form
The equation is now in the form \((x-h)^{2}=a(y-k)\) by rearranging:Multiply the entire equation by 2 to clear the fraction:\[ 2y = (x - \frac{3}{2})^2 + \frac{7}{4} \]Then,\[ (x - \frac{3}{2})^2= 2(y - \frac{7}{8}) \]
Key Concepts
Completing the SquareStandard Form of a ParabolaConic Sections
Completing the Square
Completing the square is a method used to transform a quadratic expression into a perfect square trinomial. This process simplifies the expression and often helps in solving quadratic equations or in rewriting them in a more useful form, like a standard form of a parabola. Here’s how you complete the square:
- Take the coefficient of the linear term, halve it, and square the result. For example, with a term like \(x^2 - 3x\), halve \(-3\) to get \(-\frac{3}{2}\), and square it to get \(\left(-\frac{3}{2}\right)^2 = \frac{9}{4}\).
- Add and subtract this squared term within the quadratic expression. This step helps in restructuring the expression into a square.
- Rewrite the expression as a square of a binomial plus any remaining constant terms. For example, \(x^2 - 3x + \frac{9}{4} + 4 - \frac{9}{4} = \left(x - \frac{3}{2}\right)^2 + \frac{7}{4}\).
Standard Form of a Parabola
The standard form of a parabola gives insight into its shape and position in a coordinate system. By expressing a quadratic equation in this form, you can deduce the vertex of the parabola and its direction of opening. There are two standard forms based on the orientation of the parabola:
- For parabolas opening upwards or downwards: \( (x-h)^2 = a(y-k) \). This form highlights that the parabola is centered horizontally with vertex at \(h,k\).
- For parabolas opening to the right or left: \( (y-k)^2 = a(x-h) \), showing the parabola's vertex vertically centered.
Conic Sections
Conic sections are the curves obtained by intersecting a double-napped cone with a plane. Parabolas are one of the four types of conic sections, which also include circles, ellipses, and hyperbolas. Each conic section has unique geometric properties and equations:
- **Circle:** A points equidistant from a center point, represented as \( (x-h)^2 + (y-k)^2 = r^2 \).
- **Ellipse:** An extended circle with two focal points, expressed with \( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \).
- **Parabola:** The path of all points equidistant from a focus and a directrix, often taking the form \( (x-h)^2 = a(y-k) \).
- **Hyperbola:** A curve with two distinct branches, defined by \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \).
Other exercises in this chapter
Problem 70
Write the given equation either in the form \((y-k)^{2}=a(x-h)\) or in the form \((x-h)^{2}=a(y-k)\). $$ x=3 y^{2}-6 y-2 $$
View solution Problem 70
Solve the system of equations. Give graphical support by making a sketch. $$ \begin{array}{r} x^{2}+y^{2}=4 \\ (x-1)^{2}+y^{2}=4 \end{array} $$
View solution Problem 71
Solve the system of equations. $$ \begin{aligned} \frac{x^{2}}{2}+\frac{y^{2}}{4} &=1 \\ -x^{2}+2 y &=4 \end{aligned} $$
View solution Problem 72
Write the given equation either in the form \((y-k)^{2}=a(x-h)\) or in the form \((x-h)^{2}=a(y-k)\). $$ -3 y=-x^{2}+4 x-6 $$
View solution