Problem 71
Question
What is the simplified form of \(\frac{3-\sqrt{5}}{\sqrt{5}} ?\) $$ \begin{array}{ll}{\text { A. } \frac{3 \sqrt{5}-5}{5}} & {\text { B. } \frac{5 \sqrt{3}-5}{5}} \\ {\text { C. } \sqrt{3}-\sqrt{15}} & {\text { D. } \frac{14-6 \sqrt{5}}{5}}\end{array} $$
Step-by-Step Solution
Verified Answer
The simplified form of \(\frac{3-\sqrt{5}}{\sqrt{5}}\) is \(\frac{3\sqrt{5}-5}{5}\), which matches Answer Choice A.
1Step 1: Identify the Conjugate
The conjugate of any binomial \(a + b\) is the binomial with the opposite sign in the middle: \(a - b\). Here, since we only have \(\sqrt{5}\) in our denominator, we consider this as \(0 + \sqrt{5}\). Therefore, the conjugate is \(0 - \sqrt{5}\), or \(-\sqrt{5}\).
2Step 2: Multiply by the Conjugate
Multiply the numerator and denominator by the conjugate, \(-\sqrt{5}\). This gives:\[\frac{3-\sqrt{5}}{\sqrt{5}} \times \frac{-\sqrt{5}}{-\sqrt{5}} = \frac{-3\sqrt{5}+5}{-5}\]
3Step 3: Simplify
Simplify the resulting expression:\[\frac{-3\sqrt{5}+5}{-5} = -\frac{3\sqrt{5}-5}{5}\]But since we generally prefer to avoid negative fractions, we multiply top and botton by -1:\[-\frac{3\sqrt{5}-5}{5} = \frac{3\sqrt{5}-5}{5}\]This is our final simplified form.
Key Concepts
Conjugate PairsSimplifying Radical ExpressionsAlgebraic Fractions
Conjugate Pairs
Conjugate pairs are a helpful concept in algebra, especially when dealing with binomials and radicals in denominators. When you have a binomial such as \(a + b\), its conjugate will be \(a - b\). This means you simply change the sign in the middle. Conjugates are often used to rationalize expressions, especially those with square roots in the denominator.
Using conjugates helps eliminate radicals in the denominator. When you multiply a binomial by its conjugate, you apply the difference of squares formula: \((a + b)(a - b) = a^2 - b^2\). This operation removes the radical because the result is a simple expression with no square root, allowing for further simplification.
In our exercise, \(rac{3-\sqrt{5}}{\sqrt{5}}\), we consider \(\sqrt{5}\) as \(0 + \sqrt{5}\) and identify its conjugate as \(-\sqrt{5}\). This multiplication helps turn a difficult expression into a more manageable algebraic fraction.
Using conjugates helps eliminate radicals in the denominator. When you multiply a binomial by its conjugate, you apply the difference of squares formula: \((a + b)(a - b) = a^2 - b^2\). This operation removes the radical because the result is a simple expression with no square root, allowing for further simplification.
In our exercise, \(rac{3-\sqrt{5}}{\sqrt{5}}\), we consider \(\sqrt{5}\) as \(0 + \sqrt{5}\) and identify its conjugate as \(-\sqrt{5}\). This multiplication helps turn a difficult expression into a more manageable algebraic fraction.
Simplifying Radical Expressions
Simplifying radical expressions involves reducing them into their simplest form, sometimes involving rationalization or other algebraic manipulations. Radical expressions have square roots, cube roots, or other roots, and simplifying them usually means ensuring they do not have any radicals in the denominator.
In our problem, we had \(\frac{3-\sqrt{5}}{\sqrt{5}}\), where \(\sqrt{5}\) was in the denominator. To simplify this, you multiply both the numerator and the denominator by the conjugate of the denominator, \(-\sqrt{5}\).
In our problem, we had \(\frac{3-\sqrt{5}}{\sqrt{5}}\), where \(\sqrt{5}\) was in the denominator. To simplify this, you multiply both the numerator and the denominator by the conjugate of the denominator, \(-\sqrt{5}\).
- After multiplying, you get \(-\frac{3 \sqrt{5} - 5}{5}\), leaving no radicals in the denominator.
- The expression further simplifies itself to \(\frac{3 \sqrt{5} - 5}{5}\), presenting it in the simplest form.
Algebraic Fractions
Algebraic fractions are fractions where the numerator, the denominator, or both include algebraic expressions containing variables or radicals. The main goal when working with algebraic fractions is to simplify them into their simplest form, which often involves operations like factoring, canceling common terms, and rationalizing denominators.
In dealing with the fraction \(\frac{3-\sqrt{5}}{\sqrt{5}}\), we needed to simplify the expression by rationalizing the denominator using a conjugate pair. Once this simplification is applied, the algebraic fraction becomes easier to interpret and utilize.
In dealing with the fraction \(\frac{3-\sqrt{5}}{\sqrt{5}}\), we needed to simplify the expression by rationalizing the denominator using a conjugate pair. Once this simplification is applied, the algebraic fraction becomes easier to interpret and utilize.
- We started with an expression that had a radical in the denominator, which often complicates further algebraic manipulations.
- Through multiplication by the conjugate, we change the form of the expression, resulting in an equivalent but more manageable algebraic fraction: \(\frac{3 \sqrt{5} - 5}{5}\).
Other exercises in this chapter
Problem 71
Simplify each expression. \(4^{3.5}\)
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Profit A craftsman makes and sells violins. The function \(C(x)=1000+700 x\) represents his cost in dollars to produce \(x\) violins. The function \(I(x)=5995 x
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Solve each equation. $$ 2 x^{3}-16=0 $$
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Which number is greatest? $$ \begin{array}{lllll}{\text { F. } \sqrt{0.5}} & {\text { G. } \sqrt[3]{0.5}} & {\text { H. } \sqrt[4]{0.5}} & {\text { J. } \sqrt[5
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