Problem 71
Question
Use the properties of logarithms to condense the expression.$$\log _{4} z-\log _{4} y$$.
Step-by-Step Solution
Verified Answer
The condensed form of the expression \(\log_{4} z - \log_{4} y\) is \(\log_{4} \left(\frac{z}{y}\right)\).
1Step 1: Recognize the properties of logarithms
The properties of logarithms allow us to rewrite expressions in different forms. In this case, we need the quotient rule, which states: \(\log_b(a) - \log_b(b) = \log_b\left(\frac{a}{b}\right)\). Here, \(a\) and \(b\) are positive real numbers, and \(b != 1\).
2Step 2: Apply the quotient rule
Applying the quotient rule to our expression, it rewrites the difference of two logarithms with the same base, \(\log_b(a) - \log_b(b)\), as a single logarithm of the quotient of the values: \(\log_{4} z - \log_{4} y = \log_{4} \left(\frac{z}{y}\right)\).
Key Concepts
Quotient RuleLogarithmic ExpressionsCondense Expressions
Quotient Rule
The quotient rule is a fundamental property of logarithms that simplifies the subtraction of logarithmic expressions. This rule states that when you have the difference of two logarithms with the same base, the result can be condensed into a single logarithm of a quotient. Here’s how it works:
In the given exercise, the expression \(\log _{4} z - \log _{4} y\) becomes \(\log_4\left(\frac{z}{y}\right)\). This demonstrates how the quotient rule helps in simplifying logarithmic expressions efficiently. Understanding this rule makes working with logarithms much easier and clearer, especially in solving equations and manipulating expressions.
- Consider \(\log_b(a) - \log_b(b)\). These are two logarithmic terms with the same base, \(b\).
- According to the quotient rule, this expression can be rewritten as \(\log_b\left(\frac{a}{b}\right)\).
In the given exercise, the expression \(\log _{4} z - \log _{4} y\) becomes \(\log_4\left(\frac{z}{y}\right)\). This demonstrates how the quotient rule helps in simplifying logarithmic expressions efficiently. Understanding this rule makes working with logarithms much easier and clearer, especially in solving equations and manipulating expressions.
Logarithmic Expressions
Logarithmic expressions are mathematical statements that involve logarithms, which are the inverses of exponential functions. A logarithm answers the question: "To what power must the base be raised to yield a certain number?"
For example, in \(\log_b(a)\), \(b\) is the base, \(a\) is the argument of the logarithm, and the equation is looking for the power (or logarithm) that results in \(a\).
Logarithms are useful when dealing with exponential growths and can often condense or expand mathematical equations:
For example, in \(\log_b(a)\), \(b\) is the base, \(a\) is the argument of the logarithm, and the equation is looking for the power (or logarithm) that results in \(a\).
Logarithms are useful when dealing with exponential growths and can often condense or expand mathematical equations:
- Condensing uses properties, like the quotient rule, to simplify expressions.
- Expanding can make expressions easier to compute manually by breaking them into smaller parts.
Condense Expressions
Condensing logarithmic expressions is a process used to combine multiple logarithms into a simpler, single logarithmic term using the properties of logarithms.
This helps to:
This helps to:
- Simplify complex mathematical statements, making them easier to work with.
- Streamline calculations in both algebraic computations and real-world applications.
- The quotient rule, to handle subtractions, turning them into divisions inside a logarithm.
- The product rule, to manage additions, transforming them into multiplications inside the logarithm.
- The power rule, which helps when dealing with coefficients by converting them into exponents.
Other exercises in this chapter
Problem 70
Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing utility to verify your answer. $$250\left[\frac{(1+0.01)
View solution Problem 70
Complete the table to determine the balance \(A\) for \(\$ 12,000\) invested at rate \(r\) for \(t\) years, compounded continuously.. $$\begin{array}{|c|c|c|c|c
View solution Problem 71
Write the exponential equation in logarithmic form. For example, the logarithmic form of \(e^{2}=7.3890 . . .\) is \(\ln 7.3890 . . .=2.\) $$e^{1.3}=3.6692 . .
View solution Problem 71
Solve the exponential equation algebraically. Round your result to three decimal places. Use a graphing utility to verify your answer. $$e^{2 x}-4 e^{x}-5=0$$
View solution