Problem 71
Question
Use each of the variables \(a, b, c,\) and \(d\) only once to write: a. a sum of two differences b. a difference of two sums
Step-by-Step Solution
Verified Answer
(a-b) + (c-d) is a sum of differences; (a+b) - (c+d) is a difference of sums.
1Step 1: Understand the Exercise
The goal is to use given variables, \(a, b, c,\) and \(d\), to form specific expressions: one expression must be a sum comprised of two difference expressions, and one must be a difference comprised of two sum expressions.
2Step 2: Construct a Sum of Two Differences
To construct a sum of two differences, create two separate difference expressions. For example, \( (a-b) \) and \( (c-d) \). Then, add them together: \[ (a-b) + (c-d). \]
3Step 3: Construct a Difference of Two Sums
To construct a difference of two sums, start by creating two separate sum expressions. For example, \( (a+b) \) and \( (c+d) \). Then, subtract one from the other: \[ (a+b) - (c+d). \]
Key Concepts
Understanding a Sum of DifferencesExploring a Difference of SumsDelving into Variable Expressions
Understanding a Sum of Differences
In algebra, a sum of differences is an expression where you first create differences using your variables and then add those differences together. Let's break it down with an example.
To create a sum of differences, you start by forming two difference expressions. For instance, using the variables provided:
To create a sum of differences, you start by forming two difference expressions. For instance, using the variables provided:
- First difference: \( (a-b) \)
- Second difference: \( (c-d) \)
Exploring a Difference of Sums
The idea of a difference of sums involves creating sum expressions and then finding the difference between them. This concept is the reverse of the sum of differences we just explored.
To form a difference of sums, you need two sums first. Using our variables:
To form a difference of sums, you need two sums first. Using our variables:
- First sum: \( (a+b) \)
- Second sum: \( (c+d) \)
Delving into Variable Expressions
Variable expressions are fundamental in algebra as they allow you to represent numbers or quantities that can change. Each variable stands in for an unknown value, enabling flexible equations.
In our previous examples, the variables \(a, b, c,\) and \(d\) functioned as placeholders for actual numbers. Constructing expressions like \((a-b)\) or \((a+b)\) provides a way to describe possible changes or operations without specifying exact numbers.
Creating variable expressions is essential for solving equations and inequalities. When faced with a real-world problem, a variable can represent anything from the number of apples in a basket to the distance a car travels. These expressions become tools for modeling and solving complex problems, and understanding them can open the door to mastering algebra.
In our previous examples, the variables \(a, b, c,\) and \(d\) functioned as placeholders for actual numbers. Constructing expressions like \((a-b)\) or \((a+b)\) provides a way to describe possible changes or operations without specifying exact numbers.
Creating variable expressions is essential for solving equations and inequalities. When faced with a real-world problem, a variable can represent anything from the number of apples in a basket to the distance a car travels. These expressions become tools for modeling and solving complex problems, and understanding them can open the door to mastering algebra.
Other exercises in this chapter
Problem 71
Evaluate each expression. See Example \(9 .\) $$ (4+2 \cdot 3)^{4} $$
View solution Problem 71
Insert either \(a\) symbol to make a true statement. $$ \frac{27}{22} \quad 1.2 \overline{28} $$
View solution Problem 72
Solve each equation. $$ \frac{t-1}{3}=\frac{t+2}{6}+2 $$
View solution Problem 72
Solve each equation. If the equation is an identity or a contradiction, so indicate. See Example 10. $$ 3(x-4)+6=-2(x+4)+5 x $$
View solution