Problem 71
Question
Suppose you know that \( \left\\{ a_n \right\\} \) is a decreasing sequence and all its terms lie between the numbers 5 and 8. Explain why the sequence has a limit. What can you say about the value of the limit?
Step-by-Step Solution
Verified Answer
The sequence has a limit due to the Monotone Convergence Theorem; the limit is at least 5.
1Step 1: Understanding Decreasing Sequences
A decreasing sequence is a sequence where each term is less than or equal to the preceding one: \( a_1 \geq a_2 \geq a_3 \geq \ldots \). Given that \( a_n \) is a decreasing sequence, this means it either approaches a specific value or diverges to negative infinity.
2Step 2: Identifying Bounded Sequences
The problem states that \( a_n \) lies between 5 and 8 for all terms. This implies the sequence is bounded, meaning \( 5 \leq a_n \leq 8 \) for all \( n \). Being bounded above and below is a key aspect, since it confines the terms of the sequence to a specific interval.
3Step 3: Applying the Monotone Convergence Theorem
The Monotone Convergence Theorem tells us that every bounded and monotonic sequence converges. Since \( a_n \) is both decreasing (monotonic) and bounded, the theorem guarantees that the sequence converges to a limit.
4Step 4: Determining the Value of the Limit
Because the sequence is decreasing, it will approach a lower bound. Since the sequence is bounded below by 5, this gives a concrete potential limit. Hence the limit of the sequence cannot be less than 5, and it must be the least upper bound (infimum) within the given bounds of the sequence.
Key Concepts
Decreasing SequencesBounded SequencesConvergence of Sequences
Decreasing Sequences
A decreasing sequence is one where each term is less than or equal to the term before it. This means if we have terms like \(a_1, a_2, a_3, \ldots\), then \(a_1 \geq a_2 \geq a_3 \geq \ldots\). Think about it like descending a staircase, where each step is never higher than the one you are on. In mathematical terms:
- Each term is either the same or smaller than the previous term.
- Decreasing sequences either approach a specific lower bound or could potentially dive infinitely negative.
Bounded Sequences
A bounded sequence is one where all its terms are confined within a specified range. For instance, if all terms lie between two numbers, like 5 and 8 in our case, we say the sequence is bounded. Here are some key points about bounded sequences:
- A sequence is bounded above if there is a number larger than or equal to every term in the sequence (like 8 for us).
- It is bounded below if there is a number less than or equal to every term (like 5 in our scenario).
- Being bounded helps ensure that the sequence doesn't go off to infinity in either direction.
Convergence of Sequences
When we talk about the convergence of sequences, we are discussing whether a sequence approaches a specific number as we observe more and more terms. If a sequence converges, it means there is a particular number that the sequence's terms get arbitrarily close to as you consider terms further along in the sequence. Here's what determines convergence:
- A sequence converges if it settles towards a fixed limit. Mathematically, for any small positive number \(\varepsilon\), there is a point after which all terms are within \(\varepsilon\) of the limit.
- The Monotone Convergence Theorem states that if a sequence is both monotonic and bounded, it must converge. This is why our sequence, being both decreasing and bounded, converges.
- For decreasing sequences, the limit they converge to will be the greatest lower bound of all the terms. In our exercise, since the sequence is bounded below by 5, the limit must be no less than 5.
Other exercises in this chapter
Problem 71
Use multiplication of division of power series to find the first three nonzero terms in the Maclaurin series for each function. \( y = (\arctan x)^2 \)
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A patient takes 150 mg of a drug at the same time every day. Just before each tablet is taken, \( 5% \) of the drug remains in the body. (a) What quantity of th
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Use multiplication of division of power series to find the first three nonzero terms in the Maclaurin series for each function. \( y = e^x \sin^2 x \)
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After injection of a does \( D \) of insulin, the concentration of insulin in patient's system decays exponentially and so it can be written as \( De^{-at}, \)
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