Problem 71
Question
Sketch the graph of \(r\ =\ 6\ \cos\ \theta\) over each interval.Describe the part of the graph obtained in each case. (a) \(0 \leq\ \theta\ \leq\ \dfrac{\pi}{2} \quad \quad\) (b) \(\dfrac{\pi}{2} \leq\ \theta\ \leq\ \pi\) (c) \(-\dfrac{\pi}{2} \leq\ \theta\ \dfrac{\pi}{2}\ \quad \quad\) (d) \(\dfrac{\pi}{4} \leq\ \theta\ \leq\ \dfrac{3\pi}{4}\)
Step-by-Step Solution
Verified Answer
The graph for \(r = 6\cos\theta\) will be a circle centered on the positive x-axis with a radius of 3. For each interval of \(\theta\), it will cover different parts of the circle. The parts of the circle covered are: (a) first quadrant; (b) second quadrant; (c) half-circle in the first and fourth quadrants; (d) an eighth of the circle in the first and second quadrant.
1Step 1: Identify the Curve
\(r = 6\cos\theta\) is a circle with center \((3, 0)\) and radius 3 in Cartesian coordinates.
2Step 2: Sketch Over Each Interval
(a) \(0 \leq \theta \leq \frac{\pi}{2}\): The upper semicircle (right half, \(r \geq 0\)).
(b) \(\frac{\pi}{2} \leq \theta \leq \pi\): \(r\) is negative in this interval, so the curve traces the lower semicircle.
(c) \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\): The full circle is traced.
(d) \(\frac{\pi}{4} \leq \theta \leq \frac{3\pi}{4}\): This traces the upper half of the circle.
(b) \(\frac{\pi}{2} \leq \theta \leq \pi\): \(r\) is negative in this interval, so the curve traces the lower semicircle.
(c) \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\): The full circle is traced.
(d) \(\frac{\pi}{4} \leq \theta \leq \frac{3\pi}{4}\): This traces the upper half of the circle.
Key Concepts
Polar CoordinatesGraphing Polar EquationsTrigonometric Functions
Polar Coordinates
Polar coordinates offer a unique way to specify points in a plane by two values: the radial coordinate "\(r\)" and the angular coordinate "\(\theta\)". Unlike the Cartesian system, which uses x and y coordinates to indicate position, polar coordinates focus on the distance from the origin and the angle from a reference direction, typically the positive x-axis.
Here is how you can think about it:
Here is how you can think about it:
- Radial Coordinate \(r\): It represents the distance from the origin to the point. Think of it like the radius of a circle.
- Angular Coordinate \(\theta\): It indicates the direction in which the point is located from the origin. The angle is measured in radians or degrees from the positive x-axis.
Graphing Polar Equations
Graphing polar equations can initially seem challenging, but it becomes much easier once you understand how polar coordinates work.
- The equation \(r = 6\cos\theta\) describes a circle because \(r\) changes depending on the cosine of the angle \(\theta\), with a maximum value of 6 when \(\theta = 0\).
- The nature of the trigonometric function \(\cos\theta\) dictates that maximum positive \(r\) values occur between \(0\) and \(\pi/2\), which graphically means the circle is positioned on the positive x-axis.
- Each defined interval of \(\theta\) determines a specified portion of the circle to sketch, such as quarter-circles within certain quadrants.
Trigonometric Functions
Trigonometric functions, like cosine, play a crucial role in expressing polar equations. With polar coordinates, the trigonometric functions determine how far a point is from the pole based on its angle.
- The \(\cos\theta\) function specifically affects how the radius \(r\) varies with respect to the angle \(\theta\), making \(r = 6\cos\theta\) a dynamic relationship where \(r\) stretches or shrinks as \(\theta\) changes.
- The cosine function ranges from -1 to 1, creating a loop effect whereby the radius reduces to zero at \(\pi/2\) and then begins to "mirror" itself around the y-axis for negative values of cosine.
- Such behavior is why the equation \(r = 6\cos\theta\) graphically traces out a circle centered on the x-axis.
Other exercises in this chapter
Problem 70
In Exercises 69-72, sketch the graph of the ellipse, using latera recta (see Exercise 68). \(\dfrac{x^2}{4} + \dfrac{y^2}{1} = 1\)
View solution Problem 70
REVENUE The revenue \(R\) (in dollars) generated by the sale of \(x\) units of a digital camera is given by \((x-135)^2 = -\dfrac{5}{7}(R-25,515)\). Use a graph
View solution Problem 71
In Exercises 65-84, convert the rectangular equation to polar form. Assume \(a>0\). \(y=-2\)
View solution Problem 71
WRITING Write a short paragraph explaining why parametric equations are useful.
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