Problem 71
Question
Simplify the radical expressions if possible. $$\sqrt[3]{9} \cdot \sqrt[3]{6}$$
Step-by-Step Solution
Verified Answer
The answer is \( \sqrt[3]{54} \).
1Step 1: Understanding the problem
The problem asks to simplify \( \sqrt[3]{9} \cdot \sqrt[3]{6} \). This means we need to multiply the numbers inside the cube roots, which is 9 and 6.
2Step 2: Perform the multiplication
Multiply the numbers inside the cube roots together. \( \sqrt[3]{9} \cdot \sqrt[3]{6} \) equals \( \sqrt[3]{9 \cdot 6} \) which is equal to \( \sqrt[3]{54} \).
3Step 3: Look for simplification
In the final step, we look for any possible simplification. However, 54 cannot be simplified if it remains under cube root because it is not a cube of any integer. So, our final result is \( \sqrt[3]{54} \).
Other exercises in this chapter
Problem 71
Factor completely, or state that the polynomial is prime. $$ x^{3}+2 x^{2}-9 x-18 $$
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Find each product. $$ (3 x y-1)(5 x y+2) $$
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Simplify each complex rational expression. $$\frac{\frac{1}{(x+h)^{2}}-\frac{1}{x^{2}}}{h}$$
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Write each number in decimal notation without the use of exponents. $$7.9 \times 10^{-1}$$
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