Problem 71
Question
Simplify each expression. \((4-3 i)(5+i)\)
Step-by-Step Solution
Verified Answer
The simplified form of the expression is \(23 - 11i\).
1Step 1: Apply the Distributive Property
Use the distributive property to multiply each term in the first complex number by each term in the second complex number. Perform the operations: \((4 \times 5) + (4 \times i) + (-3i \times 5) + (-3i \times i)\).
2Step 2: Multiply the Real and Imaginary Parts
Carry out the multiplication for each pair of terms: \(20 + 4i - 15i - 3i^2\). Remember that \(i^2 = -1\).
3Step 3: Combine Like Terms and Simplify
Combine the real parts and the imaginary parts separately, and replace \(i^2\) with \(-1\): \(20 - 3(-1) + (4i - 15i)\). Then simplify the expression to combine like terms.
4Step 4: Express the Simplified Form
After combining like terms and simplifying, we get the final simplified form of the given expression.
Key Concepts
Distributive PropertyReal and Imaginary PartsCombining Like Terms
Distributive Property
When simplifying complex numbers, the distributive property plays a crucial role. It allows us to multiply a single term by each term in a binomial. For instance, given a complex number multiplication like \((4-3i)(5+i)\), the distributive property dictates that we should multiply each part of the first complex number by each part of the second one.
Think of it like sharing slices of a pie evenly. Each slice (term) from the first complex number gets shared with every slice from the second. Mathematically, this gives us \((4 \times 5) + (4 \times i) + (-3i \times 5) + (-3i \times i)\). Each product represents a piece of the final answer you're putting together, like assembling a puzzle with both real numbers and imaginary units.
Think of it like sharing slices of a pie evenly. Each slice (term) from the first complex number gets shared with every slice from the second. Mathematically, this gives us \((4 \times 5) + (4 \times i) + (-3i \times 5) + (-3i \times i)\). Each product represents a piece of the final answer you're putting together, like assembling a puzzle with both real numbers and imaginary units.
Real and Imaginary Parts
Complex numbers have two distinct parts: the real part and the imaginary part. In the complex number \(a + bi\), \(a\) is the real part, and \(bi\) is the imaginary part, where \(i\) represents the square root of \(-1\).
Understanding this is crucial when simplifying complex expressions. After applying the distributive property, as you perform the multiplication, ensure you accurately multiply the real and imaginary parts. For our example, this step provides you with real components such as \(20\) and \(-3i^2\), and imaginary parts like \(4i\) and \(-15i\). Remember the special rule that \(i^2 = -1\), which helps in converting terms like \(-3i^2\) into a real number to further simplify the expression.
Understanding this is crucial when simplifying complex expressions. After applying the distributive property, as you perform the multiplication, ensure you accurately multiply the real and imaginary parts. For our example, this step provides you with real components such as \(20\) and \(-3i^2\), and imaginary parts like \(4i\) and \(-15i\). Remember the special rule that \(i^2 = -1\), which helps in converting terms like \(-3i^2\) into a real number to further simplify the expression.
Combining Like Terms
The final step in simplifying complex numbers is combining like terms. After distributing and multiplying, gather all your real parts on one side and your imaginary parts on another. From our earlier multiplication, you might see terms like \(20\) and \(-3\) (from \(-3i^2\), since \(i^2\) is -1) bear a resemblance – they are real numbers, and thus, like terms.
Similarly, combine \(4i\) and \(-15i\) since they’re both imaginary. Combining like terms helps you clean up the equation, making it more readable and easier to understand. In this case, it simplifies to \(20 - 3(-1) + (4i - 15i)\), which further simplifies to the final form once you add and subtract these figures, keeping the real and imaginary components intact.
Similarly, combine \(4i\) and \(-15i\) since they’re both imaginary. Combining like terms helps you clean up the equation, making it more readable and easier to understand. In this case, it simplifies to \(20 - 3(-1) + (4i - 15i)\), which further simplifies to the final form once you add and subtract these figures, keeping the real and imaginary components intact.
Other exercises in this chapter
Problem 71
Write each polynomial in standard form. Then classify it by degree and by number of terms. $$ -2 x^{3}-7 x^{4}+x^{3} $$
View solution Problem 71
a. The sum of two positive numbers is 4 and the sum of their cubes is \(28 .\) What is the sum of their squares? b. The product of two positive numbers 96 and t
View solution Problem 71
Use the discriminant to find the number of real solutions. $$ -x^{2}+2 x-8=0 $$
View solution Problem 72
Which term in the expansion of \((2 a-3 b)^{6}\) has coefficient 2160\(?\) \(\begin{array}{ll}{\text { F. second term }} & {\text { G. third term }} \\\ {\text
View solution