Problem 71
Question
Show that the points \((0,12),(3,0),\) and \((17 / 3,2 / 3)\) form the corners of a right triangle (that is, a triangle with a right angle).
Step-by-Step Solution
Verified Answer
Based on the calculations, the given points (0, 12), (3, 0), and (17/3, 2/3) do not form a right triangle as the Pythagorean theorem does not hold for the three sides calculated.
1Step 1: Calculate distance between Point A and Point B
We can denote the points as follows:
Point A = (0, 12)
Point B = (3, 0)
Point C = (17/3, 2/3)
The distance formula is:
\(D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)
So, the distance between Point A and Point B is:
\(D_{AB} = \sqrt{(3 - 0)^2 + (0 - 12)^2}\)
\(D_{AB} = \sqrt{3^2 + (-12)^2}\)
\(D_{AB} = \sqrt{9 + 144}\)
\(D_{AB} = \sqrt{153}\)
2Step 2: Calculate distance between Point B and Point C
Using the same distance formula, we can calculate the distance between Point B and Point C:
\(D_{BC} = \sqrt{(17/3 - 3)^2 + (2/3 - 0)^2}\)
\(D_{BC} = \sqrt{(8/3)^2 + (2/3)^2}\)
\(D_{BC} = \sqrt{(64/9) + (4/9)}\)
\(D_{BC} = \sqrt{68/9}\)
\(D_{BC} = 2\sqrt{17} / 3\)
3Step 3: Calculate distance between Point C and Point A
Now, let's calculate the distance between Point C and Point A:
\(D_{CA} = \sqrt{(0 - 17/3)^2 + (12 - 2/3)^2}\)
\(D_{CA} = \sqrt{(-17/3)^2 + (34/3)^2}\)
\(D_{CA} = \sqrt{(289/9) + (1156/9)}\)
\(D_{CA} = \sqrt{(1445/9)}\)
\(D_{CA} = 5\sqrt{13} / 3\)
4Step 4: Check if the Pythagorean theorem holds for the three sides
Now we have the lengths of the three sides, let's check if the Pythagorean theorem holds:
\((D_{AB})^2 + (D_{BC})^2 = (D_{CA})^2\)
\(153 + (4*17)/3 = (5\sqrt{13} / 3)^2\)
\(153 + 68/3 = 25*13 / 9\)
\(153*9 + 68*3 = 25*13*3\)
\(1377 + 204 = 975\)
\(1581 = 975\)
This is not true, so the points given do not form a right triangle.
Key Concepts
Understanding the Distance FormulaExploring the Pythagorean TheoremDecoding Coordinates in Geometry
Understanding the Distance Formula
The distance formula is an essential tool in geometry, helping us calculate the distance between two points on a coordinate plane. It is derived from the Pythagorean theorem and is applied by using the coordinates of the two points. This formula gives the straight-line distance, or the hypotenuse, between the two points.
Consider two points, \((x_1, y_1)\) and \((x_2, y_2)\) on a plane. To find the distance between these points, you can use the formula:
Here's an application: Measure the distance between points \(A = (0, 12)\) and \(B = (3, 0)\) using the formula. Substitute the coordinates into the formula will give the distance as \[D_{AB} = \sqrt{(3 - 0)^2 + (0 - 12)^2} = \sqrt{153}\]Understanding how to use this formula is crucial, especially when deciding if lines meet at specific angles, such as determining if they form a right triangle.
Consider two points, \((x_1, y_1)\) and \((x_2, y_2)\) on a plane. To find the distance between these points, you can use the formula:
- \[D = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
Here's an application: Measure the distance between points \(A = (0, 12)\) and \(B = (3, 0)\) using the formula. Substitute the coordinates into the formula will give the distance as \[D_{AB} = \sqrt{(3 - 0)^2 + (0 - 12)^2} = \sqrt{153}\]Understanding how to use this formula is crucial, especially when deciding if lines meet at specific angles, such as determining if they form a right triangle.
Exploring the Pythagorean Theorem
The Pythagorean theorem is a fundamental concept in mathematics, often used to determine whether a triangle is a right triangle. It states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
This can be stated as:
In practice, after calculating all three sides of a triangle, you compare them using this relation to determine if the triangle is a right triangle. In our exercise, if \((D_{AB})^2 + (D_{BC})^2\) does not equal \((D_{CA})^2\), then it does not form a right triangle.
Using the given distances:
This can be stated as:
- \(a^2 + b^2 = c^2\)
In practice, after calculating all three sides of a triangle, you compare them using this relation to determine if the triangle is a right triangle. In our exercise, if \((D_{AB})^2 + (D_{BC})^2\) does not equal \((D_{CA})^2\), then it does not form a right triangle.
Using the given distances:
- \((D_{AB})^2 = 153\)
- \((D_{BC})^2 = (2\sqrt{17}/3)^2 = 68/3\)
- \((D_{CA})^2 = (5\sqrt{13}/3)^2 = 25*13/9\)
Decoding Coordinates in Geometry
Coordinates are vital in geometry, serving as references to determine positions in a plane. Each coordinate consists of two numbers, representing the horizontal (x-axis) and vertical (y-axis) distances from a set origin point, typically represented as (0,0).
In the case of our exercise, the points given were \((0, 12), (3, 0),\) and \((17/3, 2/3)\). These points specify their locations on a Cartesian plane.
In the case of our exercise, the points given were \((0, 12), (3, 0),\) and \((17/3, 2/3)\). These points specify their locations on a Cartesian plane.
- The first point, \(A = (0, 12)\), means it's positioned "0" units to the right or left of the origin and "12" units above.
- Point \(B = (3, 0)\) is "3" units to the right of the origin and rests on the x-axis.
- Point \(C = (17/3, 2/3)\) indicates a unique position "17/3" units from the left or right and "2/3" above the x-axis.
Other exercises in this chapter
Problem 69
Explain the differences between the graphs of the equations \(y=14 x-18\) and \(y=-14 x+18\).
View solution Problem 70
Put the equation \(y=3 x t+2 x t^{2}+5\) in the form \(y=b+m x .\) What are the values of \(b\) and \(m ?\) [Note: Your answers could include \(t\).]
View solution Problem 72
(a) Find the equation of the line with intercepts (i) (2,0) and (0,5) (ii) Double those in part (i) (b) Are the two lines in part (a) parallel? Justify your ans
View solution Problem 446
A motel plans to build small rooms of size \(250 \mathrm{ft}^{2}\) and large rooms of size \(500 \mathrm{ft}^{2},\) for a total area of 16,000 \(\mathrm{ft}^{2}
View solution