Problem 71
Question
Rewrite each expression in terms of the given function or functions. \(\frac{1}{1-\cos x}-\frac{\cos x}{1+\cos x} ; \csc x\)
Step-by-Step Solution
Verified Answer
The expression \( \frac{1}{1 - \cos x} - \frac{\cos x}{1 + \cos x} \) rewritten in terms of cicant function \( \csc x \) is \( \csc^{2}x - \csc x \sec x \)
1Step 1: Utilize Pythagorean Identity
Use the identity \(1 - \cos^2 x = \sin^2 x\) to replace the \(1 - \cos x\) and \(1 + \cos x\) in the denominator. Remember that \(\csc x\) is the reciprocal of \(\sin x\). Thus, the expression is rewritten as: \(\frac{1}{\sin^2x} - \frac{\cos x}{\sin^{2}x} \)
2Step 2:Factor Out \( \csc^2 x \)
The expressions in the denominators can be converted to \( \csc^2 x \) since it's the reciprocal. The expression will then become: \( \csc^{2}x(1 - \cos x) \)
3Step 3: Simplify the Expression
Using the reciprocal of cosine function which is secant function (\(\sec x \)), the expression can be transformed to: \( \csc^{2}x(1 - \sec x) \). As a final simplification, this can be rewritten as: \( \csc^{2}x - \csc x \sec x \).
Key Concepts
Pythagorean IdentityCosecant FunctionReciprocal Identities
Pythagorean Identity
The Pythagorean identity is one of the fundamental identities in trigonometry. It relates the square of the sine function to the square of the cosine function. The identity states that:
This transformation is crucial for simplifying expressions involving trigonometric functions, especially when dealing with complex fractions.
- \( \sin^2 x + \cos^2 x = 1 \)
This transformation is crucial for simplifying expressions involving trigonometric functions, especially when dealing with complex fractions.
- Remember, substituting \( \sin^2 x \) or \( \cos^2 x \) allows you to work within a simpler trigonometric framework, often leading to a more straightforward solution.
Cosecant Function
The cosecant function, denoted as \( \csc x \), is the reciprocal of the sine function. It is defined as:
In the exercise, recognizing the relationship between \( \csc x \) and \( \sin x \) allowed us to express the terms with \( \sin^2 x \) in terms of \( \csc^2 x \).
- \( \csc x = \frac{1}{\sin x} \)
In the exercise, recognizing the relationship between \( \csc x \) and \( \sin x \) allowed us to express the terms with \( \sin^2 x \) in terms of \( \csc^2 x \).
- This simplification was key in expressing the entire original expression in a form that is easier to work with.
Reciprocal Identities
Reciprocal identities in trigonometry are a set of identities that express each basic trigonometric function as the reciprocal of another trigonometric function. The key reciprocal identities are:
For example, converting \( \frac{1}{\sin^2 x} \) directly to \( \csc^2 x \) simplifies the exercise presented in a more manageable form. Similarly, recognizing \( \sec x \) as \( \frac{1}{\cos x} \) enables transformation into expressions that are easier to interpret.
- \( \csc x = \frac{1}{\sin x} \)
- \( \sec x = \frac{1}{\cos x} \)
- \( \cot x = \frac{1}{\tan x} \)
For example, converting \( \frac{1}{\sin^2 x} \) directly to \( \csc^2 x \) simplifies the exercise presented in a more manageable form. Similarly, recognizing \( \sec x \) as \( \frac{1}{\cos x} \) enables transformation into expressions that are easier to interpret.
- The use of reciprocal identities allows for more flexibility and efficiency in simplifying trigonometric expressions, and is important for solving a wide variety of trigonometry problems.
Other exercises in this chapter
Problem 71
Rewrite each expression as a simplified expression containing one term. $$ \frac{\sin (\alpha+\beta)-\sin (\alpha-\beta)}{\cos (\alpha+\beta)+\cos (\alpha-\beta
View solution Problem 71
Use an identity to solve each equation on the interval \([0,2 \pi)\) $$ \cos 2 x=\cos x $$
View solution Problem 72
Rewrite each expression as a simplified expression containing one term. $$ \frac{\cos (\alpha-\beta)+\cos (\alpha+\beta)}{-\sin (\alpha-\beta)+\sin (\alpha+\bet
View solution Problem 72
Use an identity to solve each equation on the interval \([0,2 \pi)\) $$ \cos 2 x=\sin x $$
View solution