Problem 71
Question
Perform the operations. $$ (2 a-3 b)^{2} $$
Step-by-Step Solution
Verified Answer
The expanded form is \(4a^2 - 12ab + 9b^2\).
1Step 1: Understand the Problem
We need to square the binomial expression \((2a - 3b)\). Squaring a binomial follows the formula \((x - y)^2 = x^2 - 2xy + y^2\).
2Step 2: Apply the Squaring Formula
Identify \(x = 2a\) and \(y = 3b\) in our expression. Substitute into the formula: \((2a - 3b)^2 = (2a)^2 - 2(2a)(3b) + (3b)^2\).
3Step 3: Calculate Each Term
Calculate separately: 1. \((2a)^2 = 4a^2\)2. \(-2(2a)(3b) = -12ab\)3. \((3b)^2 = 9b^2\)
4Step 4: Combine the Terms
Combine all the calculated terms to get the final expression: \(4a^2 - 12ab + 9b^2\).
Key Concepts
Algebraic ExpressionsPolynomial ExpansionSquaring Binomials
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operators like addition or subtraction. Think of them as sentences or phrases in math language. In our exercise, the expression is \((2a - 3b)\), which includes two terms: \(2a\) and \(-3b\). Here, \(a\) and \(b\) are variables, while \(2\) and \(-3\) are coefficients.
The beauty of algebraic expressions comes from their ability to represent general situations and to be manipulated following algebraic rules. This manipulation allows us to solve expressions or simplify them, such as transforming a complicated term into something more readable or useful.
Understanding the structure of algebraic expressions is crucial because it forms the foundation for further topics in algebra like polynomial expansion or solving equations.
The beauty of algebraic expressions comes from their ability to represent general situations and to be manipulated following algebraic rules. This manipulation allows us to solve expressions or simplify them, such as transforming a complicated term into something more readable or useful.
Understanding the structure of algebraic expressions is crucial because it forms the foundation for further topics in algebra like polynomial expansion or solving equations.
Polynomial Expansion
Polynomial expansion involves taking an expression with parentheses and transforming it into a sum or a series of products without parentheses. In simpler terms, it's like opening up the brackets to see what's inside and arranging it in a readable sequence.
The binomial theorem is a cornerstone for this topic, providing a handy formula to expand expressions like \((x + y)^n\). For our exercise, we applied it to \((2a - 3b)^2\). This means identifying parts of the expression that fit the pattern and expanding them step by step.
When expanding polynomials, each term from the inner expression gets combined in every possible way with other terms. This neat process helps in revealing each component of the expression distinctly, making it easier to understand the relationships between each part.
The binomial theorem is a cornerstone for this topic, providing a handy formula to expand expressions like \((x + y)^n\). For our exercise, we applied it to \((2a - 3b)^2\). This means identifying parts of the expression that fit the pattern and expanding them step by step.
When expanding polynomials, each term from the inner expression gets combined in every possible way with other terms. This neat process helps in revealing each component of the expression distinctly, making it easier to understand the relationships between each part.
Squaring Binomials
Squaring a binomial is a special operation in algebra where a two-term expression is multiplied by itself. In our example, the expression \((2a - 3b)\) was squared. This is a typical situation where the general formula
The process includes:
- \((x - y)^2 = x^2 - 2xy + y^2\)
The process includes:
- Squaring the first term: \((2a)^2\) to get \(4a^2\).
- Multiplying both terms and doubling: \(-2(2a)(3b)\) resulting in \(-12ab\).
- Squaring the second term: \((3b)^2\) resulting in \(9b^2\).
Other exercises in this chapter
Problem 70
Use scientific notation to perform the calculations. Give all answers in scientific notation and standard notation. \(\frac{169,000,000,000}{26,000,000}\)
View solution Problem 70
Simplify. Do not use negative exponents in the answer. \(\left(11 r^{10} s^{-3}\right)^{2}\)
View solution Problem 71
Use the power of a product rule for exponents to simplify each expression. See Example \(9 .\) \(\left(-2 r^{2} s^{3}\right)^{3}\)
View solution Problem 71
Perform the operations. $$ \text { Subtract }\left(-y^{5}+5 y^{4}-1.2\right) \text { from }\left(2 y^{5}-y^{4}\right) $$
View solution