Problem 71
Question
Perform indicated operation and simplify the result. $$\frac{1}{1+\cos x}-\frac{1}{1-\cos x}$$
Step-by-Step Solution
Verified Answer
The simplified result is \( \frac{-2\cos x}{\sin^2 x} \).
1Step 1: Identify the Problem
The given expression requires simplification.\[\frac{1}{1+\cos x} - \frac{1}{1-\cos x}\] The task involves performing the subtraction of two fractions.
2Step 2: Find a Common Denominator
To subtract these fractions, we need a common denominator. The common denominator is the product of the two individual denominators:\[(1+\cos x)(1-\cos x)\]
3Step 3: Simplify the Common Denominator
Use the identity for the difference of squares to write the common denominator as:\[1 - \cos^2 x = \sin^2 x\] Hence, the new denominator becomes \( \sin^2 x \).
4Step 4: Rewrite Each Fraction with the Common Denominator
Rewrite each fraction over the common denominator \( \sin^2 x \):\[\frac{1}{1+\cos x} = \frac{1-\cos x}{\sin^2 x}, \quad \frac{1}{1-\cos x} = \frac{1+\cos x}{\sin^2 x}\]
5Step 5: Perform the Subtraction
Subtract the fractions using the common denominator:\[\frac{1-\cos x}{\sin^2 x} - \frac{1+\cos x}{\sin^2 x} = \frac{(1-\cos x) - (1+\cos x)}{\sin^2 x}\]Simplify the numerator:\[(1-\cos x) - (1+\cos x) = 1 - \cos x - 1 - \cos x = -2\cos x\]
6Step 6: Simplify the Result
Substitute the simplified numerator back over the common denominator:\[\frac{-2\cos x}{\sin^2 x}\]This is the simplified form of the original expression.
Key Concepts
Fraction SimplificationCommon DenominatorTrigonometric Functions
Fraction Simplification
When simplifying fractions like \[\frac{1}{1+\cos x} - \frac{1}{1-\cos x},\]our goal is to make the expression more manageable by converting it into a simplified form. For this particular exercise, the simplification process involves several steps to achieve a cleaner result.
- First, you identify the entire expression as a fraction with two parts (or terms) that will be subtracted.
- Next, you simplify each part by finding a common denominator, making subtraction possible.
- Finally, combine the parts and simplify as much as possible, leaving it in a form that's easy to understand and further calculate if needed.
Common Denominator
To subtract two fractions as seen in\[\frac{1}{1+\cos x} - \frac{1}{1-\cos x},\]we need a common denominator. This step is vital because it allows us to combine the fractions into a single expression.
Here's how the common denominator is found:
This simplification means both fractions can be expressed over the common denominator \(\sin^2 x\).
Here's how the common denominator is found:
- Each original fraction has a denominator: \(1+\cos x\) for the first and \(1-\cos x\) for the second.
- Multiply these denominators together to establish a common denominator, resulting in \((1+\cos x)(1-\cos x)\).
This simplification means both fractions can be expressed over the common denominator \(\sin^2 x\).
Trigonometric Functions
Trigonometric functions such as sine and cosine play a key role in this problem. The given fraction uses the cosine function, \(\cos x\), within its denominators initially.
Key trigonometric identities help simplify expressions massively:
Key trigonometric identities help simplify expressions massively:
- The identity \(1-\cos^2 x = \sin^2 x\) is crucial here. Known as the Pythagorean identity, it allows conversion of the expression to involve \(\sin^2 x\) instead.
- Simplified expressions like \(\frac{-2\cos x}{\sin^2 x}\) involve recognizing how these trigonometric functions interact with each other through identities.
Other exercises in this chapter
Problem 71
Give the exact real number value of each expression. Do not use a calculator. $$\cos ^{-1}\left(\cos \frac{3 \pi}{2}\right)$$
View solution Problem 71
Round approximate answers in radians to four decimal places and approximate answers in degrees to the nearest tenth. Write answers using the least possible nonn
View solution Problem 72
Give the exact real number value of each expression. Do not use a calculator. $$\sin ^{-1}\left(\sin \frac{3 \pi}{2}\right)$$
View solution Problem 72
Verify that each equation is an identity. $$\sin 4 \gamma=4 \sin \gamma \cos \gamma-8 \sin ^{3} \gamma \cos \gamma$$
View solution