Problem 71
Question
\(\mathrm{Fe}^{3+}\) is reduced to \(\mathrm{Fe}^{2+}\) by using (a) \(\mathrm{H}_{2} \mathrm{O}_{2}\) in presence of \(\mathrm{NaOH}\) (b) \(\mathrm{Na}_{2} \mathrm{O}_{2}\) in water (c) \(\mathrm{H}_{2} \mathrm{O}_{2}\) in presence of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) \(\mathrm{Na}_{2} \mathrm{O}_{2}\) in presence of \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
Step-by-Step Solution
Verified Answer
(c) \\mathrm{H}_{2} \\mathrm{O}_{2} in \\mathrm{H}_{2} \\mathrm{SO}_{4}
1Step 1: Reaction with H2O2 in NaOH
To find if \( \mathrm{Fe}^{3+} \) is reduced by \( \mathrm{H}_{2} \mathrm{O}_{2} \) in an alkaline medium (\( \mathrm{NaOH} \)), examine the oxidation-reduction potential. In the alkaline condition, \( \mathrm{H}_2\mathrm{O}_2 \) acts as a reducing agent. Hence, \( \mathrm{Fe}^{3+} \) will be reduced to \( \mathrm{Fe}^{2+} \).
2Step 2: Reaction with Na2O2 in Water
Consider \( \mathrm{Na}_{2} \mathrm{O}_{2} \) in water. Here, \( \mathrm{Na}_2\mathrm{O}_2 \) produces \( \mathrm{H}_2\mathrm{O}_2 \) in acidic conditions, which normally favors oxidation. Therefore, it is not effective for reducing \( \mathrm{Fe}^{3+} \) to \( \mathrm{Fe}^{2+} \) under these conditions.
3Step 3: Reaction with H2O2 in H2SO4
Investigate \( \mathrm{H}_{2} \mathrm{O}_{2} \) in a strong acid like \( \mathrm{H}_{2} \mathrm{SO}_{4} \). In acidic conditions, \( \mathrm{H}_2\mathrm{O}_2 \) acts as an oxidizing agent and is able to reduce \( \mathrm{Fe}^{3+} \) to \( \mathrm{Fe}^{2+} \).
4Step 4: Reaction with Na2O2 in H2SO4
Look at the behavior of \( \mathrm{Na}_{2} \mathrm{O}_{2} \) in the presence of \( \mathrm{H}_{2} \mathrm{SO}_{4} \). Similar to \( \mathrm{Na}_2\mathrm{O}_2 \) in water, the peroxide will produce \( \mathrm{H}_2\mathrm{O}_2 \), but due to the acidic environment, \( \mathrm{Fe}^{3+} \) will not be reduced as it tends to favor oxidation.
Key Concepts
Oxidation-Reduction PotentialReducing AgentsOxidizing Agents
Oxidation-Reduction Potential
Oxidation-reduction potential, or redox potential, is a measure that indicates the ability of a chemical species to acquire electrons and thereby be reduced. This potential is generally measured in volts and serves as a critical indicator when examining chemical reactions, especially redox reactions.
Consider it like a "pull" for electrons, similar to how gravity pulls an apple to the ground. If a substance has a high oxidation-reduction potential, it tends to pull electrons towards itself, making it more likely to be reduced.
Consider it like a "pull" for electrons, similar to how gravity pulls an apple to the ground. If a substance has a high oxidation-reduction potential, it tends to pull electrons towards itself, making it more likely to be reduced.
- If the redox potential is positive, the species can act as an oxidizing agent.
- If the potential is negative, it serves as a reducing agent.
Reducing Agents
Reducing agents are substances that donate electrons to another substance in a chemical reaction. By doing this, they themselves become oxidized, as they lose electrons.
Think of reducing agents as electron "givers"; they push electrons into other substances. When \(\mathrm{Fe}^{3+}\) is reduced, a reducing agent donates an electron, transforming it to \(\mathrm{Fe}^{2+}\).
Think of reducing agents as electron "givers"; they push electrons into other substances. When \(\mathrm{Fe}^{3+}\) is reduced, a reducing agent donates an electron, transforming it to \(\mathrm{Fe}^{2+}\).
- In alkaline conditions, such as when \(\mathrm{H}_2\mathrm{O}_2\) is combined with \(\mathrm{NaOH}\), \(\mathrm{H}_2\mathrm{O}_2\) acts as a reducing agent.
- In our problem, some conditions did not provide effective reducing agents, hence \(\mathrm{Fe}^{3+}\) remained unchanged.
Oxidizing Agents
Oxidizing agents accept electrons from another substance. By accepting electrons, they become reduced while the substance donating the electrons becomes oxidized.
Consider them as electron "acceptors." In the exercise scenario, the role of the oxidizing agent is critical in understanding whether the \(\mathrm{Fe}^{3+}\) ions in solutions can be reduced or if the opposite happens, leading to oxidation instead.
Consider them as electron "acceptors." In the exercise scenario, the role of the oxidizing agent is critical in understanding whether the \(\mathrm{Fe}^{3+}\) ions in solutions can be reduced or if the opposite happens, leading to oxidation instead.
- For instance, \(\mathrm{H}_2\mathrm{O}_2\) acts as an oxidizing agent in acidic conditions when combined with \(\mathrm{H}_2\mathrm{SO}_4\).
- This behavior shifts the balance depending on the surrounding environment.
Other exercises in this chapter
Problem 64
\(\mathrm{Mn}^{2+}\) can be oxidised to \(\mathrm{Mn} \mathrm{O}_{4}^{-}\)by \(\ldots \ldots \ldots \ldots \ldots .\) \(\left(\mathrm{SnO}_{2}, \mathrm{PbO}_{2}
View solution Problem 69
Fusion of \(\mathrm{MnO}_{2}\) with \(\mathrm{KOH}\) in presence of \(\mathrm{O}_{2}\) produces a salt \(W\). Alkaline solution of \(W\) upon electrolytic oxida
View solution Problem 72
The correct statement(s) about \(\mathrm{Cr}^{2+}\) and \(\mathrm{Mn}^{3+}\) is (are) [Atomic numbers of \(\mathrm{Cr}=24\) and \(\mathrm{Mn}=25\) ] (a) \(\math
View solution Problem 73
The pair(s) of reagents that yield paramagnetic speciesis/are (a) Na and excess of \(\mathrm{NH}_{3}\) (b) \(\mathrm{K}\) and excess of \(\mathrm{O}_{2}\) (c) \
View solution