Problem 71
Question
In each of the following cases, decide whether a precipitate will form when mixing the indicated reagents, and write a balanced equation for the reaction. (a) \(\mathrm{NaBr}(\mathrm{aq})+\mathrm{AgNO}_{3}(\mathrm{aq})\) (b) \(\mathrm{KCl}(\mathrm{aq})+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})\)
Step-by-Step Solution
Verified Answer
Precipitates form in both cases: AgBr and PbCl₂ are the precipitates.
1Step 1: Determine ion combinations
When mixing solutions, the ions from each compound dissolve in water and float around. For each pair of reactants, identify the possible cation-anion combinations that may form precipitates. These combinations are:
(a) NaBr (aq) + AgNO₃ (aq): Na⁺, Br⁻, Ag⁺, NO₃⁻ which combine to form NaNO₃ and AgBr.
(b) KCl (aq) + Pb(NO₃)₂ (aq): K⁺, Cl⁻, Pb²⁺, NO₃⁻ which combine to form KNO₃ and PbCl₂.
2Step 2: Apply solubility rules
Use solubility rules to check if any of the combinations result in a precipitate:
(a) According to solubility rules, AgBr is insoluble in water while NaNO₃ is soluble. Thus, AgBr will form as a precipitate.
(b) PbCl₂ is insoluble in water, as per solubility rules, while KNO₃ is soluble. Hence, PbCl₂ will form as a precipitate.
3Step 3: Write balanced chemical equations
For the reactions that form a precipitate, write down the balanced chemical equation:
(a) NaBr (aq) + AgNO₃ (aq) → AgBr (s) + NaNO₃ (aq)
(b) 2KCl (aq) + Pb(NO₃)₂ (aq) → PbCl₂ (s) + 2KNO₃ (aq)
Key Concepts
Solubility RulesChemical EquationsCation-Anion CombinationsInsoluble Compounds
Solubility Rules
Understanding solubility rules is essential when predicting the formation of precipitates in chemical reactions. These rules are guidelines that help us know whether an ionic compound will dissolve in water.
Key Points about Solubility Rules:
Key Points about Solubility Rules:
- Compounds containing sodium (Na⁺), potassium (K⁺), and nitrate (NO₃⁻) ions are generally soluble in water.
- Most chlorides (Cl⁻), bromides (Br⁻), and iodides (I⁻) are soluble, except when paired with silver (Ag⁺), lead (Pb²⁺), or mercury (Hg₂²⁺).
- Sulfates (SO₄²⁻) are usually soluble, with exceptions like calcium sulfate (CaSO₄), barium sulfate (BaSO₄), and lead sulfate (PbSO₄).
- Carbonates (CO₃²⁻), phosphates (PO₄³⁻), and sulfides (S²⁻) are typically insoluble, except when with alkali metals (like Na⁺, K⁺) or ammonium (NH₄⁺).
Chemical Equations
Chemical equations are expressions that describe the transformation of reactants into products in a chemical reaction. They provide a concise way to communicate chemical changes.
Start recognizing reactants and products on either side of the equation:
Example:
Start recognizing reactants and products on either side of the equation:
- Reactants are substances you begin with, on the left side of the equation.
- Products are the substances formed, listed on the right side.
Example:
- For AgBr formation: \(\text{NaBr (aq) + AgNO}_3 \text{(aq) → AgBr (s) + NaNO}_3 \text{(aq)}\)
- For PbCl₂ formation: \(2\text{KCl (aq) + Pb(NO}_3\text{)}_2\text{(aq) → PbCl}_2\text{(s) + 2KNO}_3\text{(aq)}\)
Cation-Anion Combinations
Cation-anion combinations occur when positively charged ions (cations) and negatively charged ions (anions) associate to form compounds. In aqueous solutions, ions dissociate and can recombine when different solutions are mixed.
In the examples given, the cation of one reactant meets the anion of the other, resulting in either soluble or insoluble compounds. For instance:
- Cations within the exercise include Na⁺, K⁺, Ag⁺, and Pb²⁺.
- Anions include Br⁻, Cl⁻, and NO₃⁻.
In the examples given, the cation of one reactant meets the anion of the other, resulting in either soluble or insoluble compounds. For instance:
- Na⁺ + NO₃⁻ form soluble NaNO₃.
- Ag⁺ + Br⁻ form the insoluble compound AgBr (precipitate).
- K⁺ + NO₃⁻ form soluble KNO₃.
- Pb²⁺ + Cl⁻ form the insoluble compound PbCl₂ (precipitate).
Insoluble Compounds
Insoluble compounds are those that do not dissolve significantly in water, resulting in the formation of a solid precipitate when solutions combine during a reaction. Understanding why certain compounds are insoluble helps in predicting the outcome of an ionic reaction.
Substances with certain ion pairs, like silver bromide (AgBr) or lead chloride (PbCl₂), are known to be insoluble. Upon interaction:
Substances with certain ion pairs, like silver bromide (AgBr) or lead chloride (PbCl₂), are known to be insoluble. Upon interaction:
- AgBr is formed when Ag⁺ and Br⁻ combine, precipitating as a solid because it does not dissolve in water.
- PbCl₂ forms under similar circumstances from Pb²⁺ and Cl⁻, appearing as a solid precipitate.
Other exercises in this chapter
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