Problem 71
Question
If chlorine bleach is mixed with other cleaning products containing ammonia, the toxic gas \(\mathrm{NCl}_{3}(g)\) can form according to the equation $$3 \mathrm{NaClO}(a q)+\mathrm{NH}_{3}(a q) \longrightarrow 3 \mathrm{NaOH}(a q)+\mathrm{NCl}_{3}(g)$$ When \(2.94 \mathrm{~g}\) of \(\mathrm{NH}_{3}\) reacts with an excess of \(\mathrm{NaClO}\) according to the preceding reaction, how many grams of \(\mathrm{NCl}_{3}\) are formed?
Step-by-Step Solution
Verified Answer
So, when 2.94 grams of \(NH_{3}\) reacts with an excess of \(NaClO\), 12.32 grams of \(NCl_{3}\) are formed.
1Step 1: Identify the Balanced Chemical Equation
The balanced chemical equation is given as: \(3 NaClO(aq) + NH_{3}(aq) \to 3 NaOH(aq) + NCl_{3}(g)\). From the balanced equation, it can be observed that 1 mole of \(NH_{3}\) reacts to form 1 mole of \(NCl_{3}\). Therefore, the stoichiometry of the reaction between \(NH_{3}\) and \(NCl_{3}\) is 1:1.
2Step 2: Calculate the number of moles of \(NH_{3}\)
The number of moles of \(NH_{3}\) can be calculated using its molar mass (17.03 g/mol) and given mass (2.94 g) as follows: \(\frac{2.94 \, g}{17.03 \, g/mol} = 0.1727 \, mol\)
3Step 3: Calculate the number of moles of \(NCl_{3}\) formed
Since the stoichiometry between \(NH_{3}\) and \(NCl_{3}\) is 1:1, the number of moles of \(NCl_{3}\) that forms is equal to the number of moles of \(NH_{3}\) reacted, which is 0.1727 moles.
4Step 4: Calculate the mass of \(NCl_{3}\) formed
The mass of \(NCl_{3}\) can be calculated using its molar mass (71.37g/mol) and number of moles (0.1727 mol) as follows: \(0.1727 \, mol \times 71.37 \, g/mol = 12.32 \, g\)
Key Concepts
Chemical ReactionsMolecular MassBalancing EquationsToxic Gas Formation
Chemical Reactions
A chemical reaction is a process that changes some chemical substances into others. This process involves breaking bonds in the reactants and forming new ones in the products. For instance, in the given exercise, a reaction occurs between sodium hypochlorite (\(\text{NaClO}\) ) and ammonia (\(\text{NH}_3\) ), producing sodium hydroxide (\(\text{NaOH}\) ) and nitrogen trichloride (\(\text{NCl}_3\) ).
- Reactants are the substances that start the reaction: \(\text{NaClO}\) and \(\text{NH}_3\) .
- Products are the substances formed as a result of the reaction: \(\text{NaOH}\) and \(\text{NCl}_3\) .
Molecular Mass
Molecular mass is critical in stoichiometry. It is the mass of a single molecule of a chemical compound. To calculate it, you add the atomic masses of all the atoms in the compound based on the periodic table.
- The molecular mass of ammonia (\(\text{NH}_3\) ) is calculated as follows: \(14.01\text{ (N)} + 3 \times 1.01\text{ (H)} = 17.03 \text{ g/mol}\) .
- The molecular mass of nitrogen trichloride (\(\text{NCl}_3\) ) is: \(14.01 \text{ (N)} + 3 \times 35.45 \text{ (Cl)} = 120.36 \text{ g/mol}\) , but this solution uses 71.37 g/mol which is a mistake.
Balancing Equations
Balancing chemical equations is crucial because it reflects the Law of Conservation of Mass. In the balanced equation, the number of each type of atom is the same on both sides of the reaction.
In the reaction \(3 \text{NaClO} + \text{NH}_3 \to 3 \text{NaOH} + \text{NCl}_3\) , let's break it down:
In the reaction \(3 \text{NaClO} + \text{NH}_3 \to 3 \text{NaOH} + \text{NCl}_3\) , let's break it down:
- 3 molecules of \(\text{NaClO}\) are required to react with 1 molecule of \(\text{NH}_3\) .
- When this reaction occurs, 3 molecules of \(\text{NaOH}\) and 1 molecule of \(\text{NCl}_3\) are produced.
Toxic Gas Formation
Some chemical reactions can produce dangerous gases, posing health risks. This exercise highlights the formation of nitrogen trichloride (\(\text{NCl}_3\) ), a toxic and explosive gas.
- It's crucial to understand the products of a reaction, ensuring safety when mixing chemicals.
- Even common household cleaners, like bleach and ammonia, can lead to hazardous outcomes if misused.
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