Problem 71

Question

Find the limit. $$ \lim _{x \rightarrow 3^{+}} \ln \left(x^{2}-9\right) $$

Step-by-Step Solution

Verified
Answer
The limit is \(-\infty\).
1Step 1: Identify the Function and the Direction
We are given the limit \( \lim _{x \rightarrow 3^{+}} \ln (x^{2} - 9) \). This means we need to focus on how the natural log function \( \ln(y) \) behaves as \( y = x^2 - 9 \) approaches zero from the positive side as \( x \) approaches 3 from the right.
2Step 2: Substitute Specific Values and Analyze Behavior
As \( x \) approaches 3 from the right, \( x \) can be thought of as a number slightly greater than 3, say \( x = 3 + \epsilon \) where \( \epsilon \) is small and positive. This makes \( x^2 - 9 = (3 + \epsilon)^2 - 9 = 9 + 6\epsilon + \epsilon^2 - 9 = 6\epsilon + \epsilon^2 \), which approaches 0 from the positive side as \( \epsilon \) approaches 0.
3Step 3: Recognize the Limit Behavior of the Logarithm Function
The function \( \ln(y) \) tends to \(-\infty\) as \( y \rightarrow 0^{+} \). Since \( x^2 - 9 \rightarrow 0^{+} \) when \( x \rightarrow 3^{+} \), the expression \( \ln(x^2 - 9) \rightarrow -\infty \).
4Step 4: Write the Final Limit
Thus, the limit \( \lim _{x \rightarrow 3^{+}} \ln (x^{2} - 9) \) is equal to \(-\infty\).

Key Concepts

Understanding the Natural LogarithmBehavior of Functions and LimitsLimit Approaching from the Right
Understanding the Natural Logarithm
The natural logarithm, denoted as \( \ln(x) \), is a special logarithmic function that uses the mathematical constant "\( e \)" as its base. This constant, \( e \),approximates 2.718281828 and appears frequently in calculus, owing to its natural properties.

Key points to understand about the natural logarithm:
  • Domain: The function \( \ln(x) \) is defined only for positive values of \( x \).If \( x = 0 \), the natural logarithm is undefined, and if \( x < 0 \), it is not considered within real numbers.
  • Properties: \( \ln(1) = 0 \) since any number to the power of 0 is 1.For values of \( x \) inside (0,1), the natural logarithm returns negative outputs,whereas for values of \( x > 1 \), it yields positive outputs.
  • Behavior as \( x \rightarrow 0^{+} \): As \( x \) approaches 0 from the positive side (\( x \rightarrow 0^{+} \)),\( \ln(x) \) approaches \( -\infty \). This means that even though \( x \) doesn't become negative,the logarithm declines sharply.