Problem 71
Question
Factor. $$ x^{4}+x^{2}-20 $$
Step-by-Step Solution
Verified Answer
The expression factors to \((x^2 + 5)(x - 2)(x + 2)\).
1Step 1: Identify Quadratic Form
The expression provided is a polynomial of degree 4: \( x^4 + x^2 - 20 \). Notice it can be viewed as a quadratic in terms of \( x^2 \) because the exponents of the terms are powers of two. So, consider substituting \( y = x^2 \). This transforms the expression into \( y^2 + y - 20 \).
2Step 2: Factor the Quadratic
Next, factor the quadratic expression \( y^2 + y - 20 \). We need two numbers whose product is \(-20\) and sum is \(1\). These numbers are \(5\) and \(-4\). So, the expression factors as \( (y + 5)(y - 4) \).
3Step 3: Substitute Back to Original Variable
Now that we have factored in terms of \( y \), we substitute back \( y = x^2 \). Therefore, the expression becomes \( (x^2 + 5)(x^2 - 4) \).
4Step 4: Further Factor if Possible
The factor \( x^2 - 4 \) is a difference of squares, which can be further factored. Use the identity \( a^2 - b^2 = (a+b)(a-b) \). Thus, \( x^2 - 4 = (x - 2)(x + 2) \).
5Step 5: Write the Complete Factored Form
Now write down the complete factorization using all factored forms: \( x^4 + x^2 - 20 = (x^2 + 5)(x - 2)(x + 2) \).
Key Concepts
Quadratic FormDifference of SquaresSubstitution Method
Quadratic Form
A quadratic form is a type of polynomial that typically appears in the format \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. It represents any polynomial expression where the greatest exponent of the variable is 2. In the exercise, although starting with a degree 4 polynomial, we identified it could be viewed in quadratic form by treating \( x^2 \) as a single variable.
This simplification allows us to rewrite our expression, \( x^4 + x^2 - 20 \), into the form \( y^2 + y - 20 \) by substituting \( y = x^2 \). This makes it easier to factor, as it transforms a potentially complex degree 4 polynomial into a more manageable quadratic.
This simplification allows us to rewrite our expression, \( x^4 + x^2 - 20 \), into the form \( y^2 + y - 20 \) by substituting \( y = x^2 \). This makes it easier to factor, as it transforms a potentially complex degree 4 polynomial into a more manageable quadratic.
- Identify how the expression or part of it can fit this form.
- Perform substitutions to simplify complex polynomials into quadratic form.
- Focus on recognizing patterns of exponents like squares.
Difference of Squares
The difference of squares is a specific algebraic formula, namely \( a^2 - b^2 = (a+b)(a-b) \), used to factor expressions involving two perfect squares with subtraction. This concept becomes handy when you spot terms like \( x^2 - 4 \) in this exercise.
In a difference of squares, you are looking for:
In a difference of squares, you are looking for:
- Two terms that are each perfect squares.
- A subtraction between them.
Substitution Method
The substitution method is a valuable tool for simplifying polynomial factorization. It involves replacing a complex part of a polynomial with a simpler variable to make the equation easier to handle. In our exercise, this is accomplished by substituting \( y = x^2 \).
This makes handling the polynomial \( x^4 + x^2 - 20 \) feasible by converting it to the quadratic \( y^2 + y - 20 \). The process of substitution simplifies the equation structurally:
This makes handling the polynomial \( x^4 + x^2 - 20 \) feasible by converting it to the quadratic \( y^2 + y - 20 \). The process of substitution simplifies the equation structurally:
- Choose an appropriate substitution to reduce complexity.
- Solve or factor the equation in the new variable.
- Replace back to the original variable after simplification or factorization.
Other exercises in this chapter
Problem 70
Solve each equation. $$ \frac{10}{z}=\frac{5}{z}-\frac{1}{3} $$
View solution Problem 70
Solve each inequality. See Section 2.7. $$ \frac{2 x}{3}+\frac{1}{6} \geq 2 $$
View solution Problem 71
Solve each inequality. See Section 2.7. $$ \frac{y-1}{15}>-\frac{2}{5} $$
View solution Problem 71
Neglecting air resistance, the distance \(s(t)\) in feet traveled by a freely falling object is given by the function \(s(t)=16 t^{2}\), where t is time in seco
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