Problem 71
Question
Explain how to find \(n !\) if \(n\) is a positive integer.
Step-by-Step Solution
Verified Answer
The factorial of a positive integer \(n\), denoted by \(n!\), is the product of all positive integers less than or equal to \(n\). For 0 and 1, the factorial is 1. The factorial can be found by starting from 1 and multiplying all integers up to \(n\).
1Step 1: Understanding Factorial
The factorial of a positive integer \(n\) is denoted by \(n!\) and is the product of all positive integers less than or equal to \(n\). In other words: \(n! = n \times (n-1) \times (n-2) \times \ldots \times 2 \times 1\)
2Step 2: Special Cases
For the numbers 0 and 1, the factorial is defined as 1. That means \(0!\) and \(1!\) = 1.
3Step 3: Finding Factorial
To find the factorial of any positive integer \(n\), start from 1 and multiply all integers up to \(n\). For example, if \(n = 5\), then \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).
Other exercises in this chapter
Problem 71
Use the Binomial Theorem to expand and then simplify the result: \(\left(x^{2}+x+1\right)^{3}\). [ Hint: Write \(x^{2}+x+1\) as \(\left.x^{2}+(x+1)\right]\)
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Use the formula for the value of an annuity. Round answers to the nearest dollar. You contribute 600 dollar at the end of each quarter to a \(\operatorname{Tax}
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In the sequence \(21,700,23,172,24,644,26,116, \ldots,\) which term is \(314,628 ?\)
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How many four-digit odd numbers less than 6000 can be formed using the digits \(2,4,6,7,8,\) and \(9 ?\) Digits may be repeated.
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