Problem 71
Question
Exercises \(67-78\) give parametric equations and parameter intervals for the
motion of a particle in the \(x y\) -plane. Identify the particle's path by
finding a Cartesian equation for it. Graph the Cartesian equation. The graphs
will vary with the equation used.) Indicate the portion of the graph traced by
the particle and the direction of motion.
$$
x=3 t, \quad y=9 t^{2}, \quad-\infty
Step-by-Step Solution
Verified Answer
The particle's path is a parabola, \( y = x^2 \), traced from left to right.
1Step 1: Convert Parametric Equations to Cartesian Equation
To find the Cartesian equation, we need to eliminate the parameter \( t \) from the equations. We have \( x = 3t \) and \( y = 9t^2 \). Solve for \( t \) from \( x = 3t \): \( t = \frac{x}{3} \). Substitute this into \( y = 9t^2 \) to get \( y = 9 \left( \frac{x}{3} \right)^2 = y = 9 \cdot \frac{x^2}{9} = x^2 \).
2Step 2: Write the Cartesian Equation
After substitution and simplification, we obtain the Cartesian equation of the curve as \( y = x^2 \). This represents a parabola opening upwards.
3Step 3: Determine the Graph and Direction of Motion
The Cartesian equation \( y = x^2 \) is a standard parabola. The direction of motion is determined by observing the parameter \( t \). As \( t \) moves from \(-\infty\) to \(+\infty\), \( x = 3t \) implies \( x \) also covers its entire range from \(-\infty\) to \(+\infty\). This means the particle moves along the parabola from left to right as \( t \) increases.
4Step 4: Graph the Cartesian Equation and Motion
Graph the parabola \( y = x^2 \) on the coordinate plane. Indicate the path of the particle with arrows moving from left to right along the parabola, as \( t \) changes from \(-\infty\) to \(+\infty\). The entire parabola is traced due to the given range of \( t \).
Key Concepts
Cartesian EquationParticle MotionGraphing Parabolas
Cartesian Equation
In mathematics, a Cartesian equation describes a relationship between the x and y coordinates in a plane, eliminating any parameter variables. This approach turns parametric equations into one overarching equation that captures the path of a curve on the Cartesian plane.
For example, certain motions in physics or geometry, such as a particle's path, might initially be expressed with parametric equations like \( x = 3t \) and \( y = 9t^2 \). Here, \( t \) serves as a parameter representing time, which can be eliminated to derive a clearer two-dimensional representation.
For example, certain motions in physics or geometry, such as a particle's path, might initially be expressed with parametric equations like \( x = 3t \) and \( y = 9t^2 \). Here, \( t \) serves as a parameter representing time, which can be eliminated to derive a clearer two-dimensional representation.
- Start with the first equation \( x = 3t \) to solve for the parameter: \( t = \frac{x}{3} \).
- Next, substitute \( t \) in the second equation, \( y = 9t^2 \), leading to \( y = 9(\frac{x}{3})^2 \), which simplifies to \( y = x^2 \).
Particle Motion
Exploring particle motion involves understanding how an object's position changes over time, often modeled through equations with a time parameter like \( t \).
This kind of motion can initially be presented with parametric equations, providing separate expressions for position coordinates based on \( t \). For a particle traveling through the plane, the parametric equations \( x = 3t \) and \( y = 9t^2 \) define its precise location at any moment in time.
This kind of motion can initially be presented with parametric equations, providing separate expressions for position coordinates based on \( t \). For a particle traveling through the plane, the parametric equations \( x = 3t \) and \( y = 9t^2 \) define its precise location at any moment in time.
- As \( t \) progresses over its full range from \(-\infty \) to \(+\infty \), it influences \( x \) and \( y \) values according to these equations.
- This leads to the conclusion that the particle's path covers an endless range along the Cartesian plane.
- The key aspect is the particle's trajectory, represented by the equation \( y = x^2 \) in Cartesian coordinates.
Graphing Parabolas
A fundamental feature associated with parabolas is their standard form, often represented as \( y = ax^2 + bx + c \), where \( a, b, \) and \( c \) define the parabola's shape and position. In this problem, the parametric equations simplify to the Cartesian form \( y = x^2 \), emblematic of an upward-opening parabola.
A parabola appears as a U-shaped curve on the graph, symmetrical around its vertical axis.
A parabola appears as a U-shaped curve on the graph, symmetrical around its vertical axis.
- The vertex, positioned at the origin \((0,0)\) in this case, is the lowest point because the parabola opens upwards.
- To graph \( y = x^2 \), plot symmetric points on either side of \( x = 0 \), such as \( (-2,4), (-1,1), (0,0), (1,1), (2,4) \).
- Connect these points to form the parabola, ensuring it reflects the mathematical elegance of symmetry.
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