Problem 71
Question
Describe how to find the inverse of a one-to-one function.
Step-by-Step Solution
Verified Answer
The inverse of the one-to-one function \( f(x) = 2x + 3 \) is \( f^{-1}(x) = (x - 3) / 2 \).
1Step 1: Identify the Function
The first step is identifying the function to be inversed. It is assumed that a one-to-one function is given, such as a line, a logarithm or an exponential function. Let's take, for illustrative purposes, the function \( f(x) = 2x + 3 \).
2Step 2: Swap x and y variables
The second step is swapping the variables. This means, wherever there is an x, replace it with y and wherever there is y or f(x), replace it with x. So, \( f(x) = 2x + 3 \) becomes \( f^{-1}(y) = 2y + 3 \), or simply \( x = 2y + 3 \).
3Step 3: Solve for the new y
The third step is solving for the new y, meaning we need to isolate y in the equation got at previous step. By simple algebra, the equation becomes \( y = (x - 3) / 2 \).
4Step 4: Replace the new y with inverse notation
Finally, replace the new y with inverse notation. Therefore, \( y = (x - 3) / 2 \) becomes \( f^{-1}(x) = (x - 3) / 2 \), which represents the inverse of the original function.
Other exercises in this chapter
Problem 70
Use intercepts to graph each equation. \(3 x+5 y+15-0\)
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Find a. \((f \circ g)(x)\) b. the domain of \(f^{\circ}\) g. $$ f(x)-\frac{x}{x+5}, g(x)=\frac{6}{x} $$
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Begin by graphing the square root function, \(f(x)-\sqrt{x} .\) Then use transformations of this graph to graph the given function. $$ h(x)--\sqrt{x+2} $$
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Use intercepts to graph each equation. \(8 x-2 y+12-0\)
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