Problem 71
Question
Compute the indefinite integrals. $$ \int \frac{\cos x}{1-\cos ^{2} x} d x $$
Step-by-Step Solution
Verified Answer
The indefinite integral is \( -\csc x + C \).
1Step 1: Identify the Trigonometric Identity
Recognize that the denominator can be simplified using the Pythagorean identity: \( 1 - \cos^2 x = \sin^2 x \). Therefore, the integral becomes \( \int \frac{\cos x}{\sin^2 x} \, dx \).
2Step 2: Simplify the Integrand
Rewrite the integrand \( \frac{\cos x}{\sin^2 x} \) as \( \frac{1}{\sin^2 x} \cdot \cos x = \cot x \csc x \).
3Step 3: Integrate Using Known Formula
Recall the known integral \( \int \cot x \csc x \, dx = -\csc x + C \). Apply this formula to compute \( \int \cot x \csc x \, dx \).
4Step 4: Write the Final Answer
The integral evaluates to \( -\csc x + C \), where \( C \) is the constant of integration.
Key Concepts
Trigonometric IdentitySimplifying IntegrandsIntegral Formulas
Trigonometric Identity
Trigonometric identities are essential tools in simplifying and solving integrals involving trigonometric functions. In the given exercise, recognizing and applying a trigonometric identity is the crucial first step. We encounter an expression in the denominator: \( 1 - \cos^2 x \). By applying the Pythagorean identity, \( 1 - \cos^2 x = \sin^2 x \), we can transform this expression.
The Pythagorean identities are fundamental in trigonometry, providing relationships between the sine and cosine of an angle:
The Pythagorean identities are fundamental in trigonometry, providing relationships between the sine and cosine of an angle:
- \( \sin^2 x + \cos^2 x = 1 \)
- \( 1 - \cos^2 x = \sin^2 x \)
- \( 1 - \sin^2 x = \cos^2 x \)
Simplifying Integrands
Simplifying the integrand is a helpful technique that turns complicated expressions into simpler forms, making integration more feasible. In this exercise, after using the trigonometric identity, the integrand becomes \( \frac{\cos x}{\sin^2 x} \). To simplify further, we separate the fraction into a product of two known trigonometric identities.
Let's see how this is done:
Let's see how this is done:
- Express \( \frac{\cos x}{\sin^2 x} \) as \( \frac{1}{\sin^2 x} \cdot \cos x \)
- We recognize \( \frac{1}{\sin^2 x} \) as \( \csc^2 x \) and \( \cos x \) as part of \( \cot x \cdot \csc x \)
- Thus, the integrand simplifies to \( \cot x \csc x \).
Integral Formulas
Integral formulas are like shortcuts that allow us to solve integrals quickly without recalculating everything from scratch. In our example, once we simplify the integrand to \( \cot x \csc x \), we can use a readily available integral formula to find the solution.
This formula is based on standard integrals:
This formula is based on standard integrals:
- \( \int \cot x \csc x \, dx = -\csc x + C \)
Other exercises in this chapter
Problem 70
Compute the indefinite integrals. $$ \int \frac{\cos x}{1-\cos ^{2} x} d x $$
View solution Problem 70
Find \(\int_{-3}^{-3} e^{-x^{2} / 2} d x\).
View solution Problem 71
Find \(\int_{-2}^{2} \frac{x^{3}}{3} d x\)
View solution Problem 72
Compute the indefinite integrals. $$ \int \cot (3 x) d x $$
View solution