Problem 71
Question
At an underwater depth of \(100 \mathrm{~m}\), the pressure is \(1.106 \mathrm{MPa}\). What should the partial pressure of oxygen be in the diving gas for the mole fraction of oxygen in the mixture to be 0.21 , the same as in air?
Step-by-Step Solution
Verified Answer
The partial pressure of oxygen should be 232.26 kPa.
1Step 1: Calculate the Total Pressure Underwater
First, let's establish that the underwater pressure at a depth of 100 meters is given as 1.106 Megapascals (MPa). This is the absolute pressure acting on the diving gas mixture.
2Step 2: Convert the Pressure to Kilopascals
The pressure is provided in MPa. To convert that to kilopascals (kPa), we use the conversion: 1 MPa = 1000 kPa. Therefore, \(1.106 \text{ MPa} = 1106 \text{ kPa}\).
3Step 3: Apply Raoult's Law for Partial Pressure
Raoult’s Law states that the partial pressure of a gas in a mixture is the product of the total pressure and the mole fraction of the gas. Here, the mole fraction \(x\) of oxygen is given as 0.21. Therefore, the partial pressure of oxygen is: \(P_{O_2} = 1106 \text{ kPa} \times 0.21\).
4Step 4: Calculate the Partial Pressure of Oxygen
Perform the multiplication from Step 3: \(P_{O_2} = 1106 \text{ kPa} \times 0.21 = 232.26 \text{ kPa}\).
5Step 5: Conclusion
The partial pressure of oxygen at an underwater depth of 100 meters, for a mole fraction of 0.21, should be 232.26 kPa.
Key Concepts
Raoult's LawMole FractionUnderwater Pressure
Raoult's Law
Raoult's Law is a fundamental principle used to determine the partial pressure of a component in a mixture. This law is particularly helpful for understanding solutions like diving gases. The law states that the partial pressure of a component gas is directly proportional to its mole fraction in the mixture. In simpler terms, this means:
- Partial pressure = Total pressure × Mole fraction of the gas
Mole Fraction
The mole fraction is a way to express the concentration of a component in a mixture. It's a simple ratio, showing how many moles of a particular component are present compared to the total number of moles of all components combined. In mathematical terms:
- Mole fraction = Moles of the component / Total moles of the mixture
Underwater Pressure
When we delve underwater, the pressure increases significantly compared to the surface. At a depth of 100 meters, the pressure is approximately 1.106 MPa, far greater than the atmospheric pressure of 0.1013 MPa at sea level. This increased pressure affects the gases divers breathe in their tanks. It compresses the gas, thus increasing its density and requiring divers to manage these conditions.
Underwater pressure directly affects the partial pressures of the gases in a diving mixture. Divers must adjust their gear to ensure that the partial pressures remain within safe levels to prevent conditions like nitrogen narcosis or oxygen toxicity. Specifically, using Raoult’s Law, divers calculate necessary partial pressures to ensure safe breathing mixtures, avoiding excessive or insufficient oxygen supply while underwater.
Other exercises in this chapter
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