Problem 70
Question
Write each expression as a single logarithm. \(\log _{5} x-\frac{1}{5} \log _{5} y\)
Step-by-Step Solution
Verified Answer
The expression \(\log _{5} x-\frac{1}{5} \log _{5} y\) as a single logarithm is \(\log _{5} \(\frac{x}{ y^\frac{1}{5}}\)\).
1Step 1: Analyze the given expression
The given expression is \(\log _{5} x-\frac{1}{5} \log _{5} y\). It contains two logarithms with the same base (5) that are subtracted from each other.
2Step 2: Apply power rule of logarithms
Apply the power rule of logarithms to the second part of the expression. This means moving the coefficient \(\frac{1}{5}\) inside the logarithm and raising the argument y to that power. By doing so, \(\frac{1}{5} \log _{5} y\) becomes \(\log _{5} y^\frac{1}{5}\). The expression then becomes \(\log _{5} x - \log _{5} y^\frac{1}{5}\).
3Step 3: Apply subtraction rule of logarithms
Apply the rule of subtraction for logarithms to the expression. This states that the rule turns a subtraction of logarithms into a division inside one logarithm. By applying that rule, \(\log _{5} x - \log _{5} y^\frac{1}{5}\) becomes \(\log _{5} \(\frac{x}{ y^\frac{1}{5}}\)\). This is the final single logarithm expression.
Key Concepts
Power Rule of LogarithmsSubtraction Rule of LogarithmsSimplifying Logarithms
Power Rule of Logarithms
In the world of logarithms, there's a very handy tool known as the power rule. This rule tells us how to deal with coefficients in front of log expressions. If you see an expression like \(c \log_b a\), you can use the power rule to rewrite it as \( \log_b a^c \). This means you move the coefficient \(c\) up as an exponent in the argument of the log. In our example, we had \(\frac{1}{5} \log_5 y\). Using the power rule, we raised \(y\) to the power of \(\frac{1}{5}\), changing the expression to \(\log_5 y^{\frac{1}{5}}\). This makes it easier to combine log terms as we'll see in the next sections. By understanding and using the power rule, you can simplify and manipulate logarithmic expressions effectively.
Subtraction Rule of Logarithms
One useful property of logarithms is how subtraction between two logs can be simplified. The subtraction rule is our guide here. This says that \( \log_b a - \log_b c\) can be rewritten as \( \log_b \frac{a}{c} \).This rule is particularly useful when dealing with expressions that involve subtraction. In the original exercise, after applying the power rule, the expression was \( \log_5 x - \log_5 y^{\frac{1}{5}} \). The subtraction rule allowed us to combine these into a single logarithmic expression: \( \log_5 \left( \frac{x}{y^{\frac{1}{5}}} \right) \). Understanding this rule not only helps with simplifying expressions, but it also paves the way for more advanced algebraic manipulations.
Simplifying Logarithms
Simplifying logarithmic expressions means using rules like the power rule and subtraction rule to neatly combine terms into a more manageable form. In this exercise, after implementing the power rule and the subtraction rule, we condensed the expression \( \log_5 x - \frac{1}{5} \log_5 y \) into \( \log_5 \left( \frac{x}{y^{\frac{1}{5}}} \right) \).The idea is to express complex logarithmic statements into simpler, single-logarithm forms. This not only makes computations easier but often reveals insights or patterns that weren't obvious before. To simplify successfully:
- Look for opportunities to apply logarithm rules.
- Simplify step-by-step using known properties.
- Ensure that the base of all the logs involved match.
Other exercises in this chapter
Problem 69
Multiply and simplify. Assume that all variables are positive. $$ 3 \sqrt[3]{4 x^{2}} \cdot 7 \sqrt[3]{12 x^{4}} $$
View solution Problem 70
Solve each equation. $$ 2 e^{2 x}+1=5 $$
View solution Problem 70
Solve each equation. $$ \log _{0.1}(x+1)=3 $$
View solution Problem 70
Multiply. \((\sqrt{3}+\sqrt{5})(\sqrt{3}-\sqrt{5})\)
View solution