Problem 70
Question
Which of the following is diamagnetic? (a) \(\mathrm{H}_{2}^{+}\) (b) \(\mathrm{O}_{2}\) (c) \(\mathrm{Li}_{2}\) (d) \(\mathrm{He}_{2}^{+}\)
Step-by-Step Solution
Verified Answer
\\(\mathrm{Li}_{2}\\)
is diamagnetic because all its electrons are paired.
1Step 1: Understanding Diamagnetism
Diamagnetism is a property of materials that have all their electrons paired. Such substances are weakly repelled by a magnetic field. To determine which molecule is diamagnetic, identify which one has all paired electrons in its molecular orbitals.
2Step 2: Examine \\(\mathrm{H}_{2}^{+}\\)
The \(\mathrm{H}_{2}^{+}\) ion has one electron, so it has an unpaired electron. Thus, it is paramagnetic.
3Step 3: Examine \\(\mathrm{O}_{2}\\)
Oxygen (\(\mathrm{O}_{2}\)) has 12 electrons in its molecular orbital configuration. The outermost molecular orbitals are \(\pi^*_{2p}\), each with one unpaired electron, making it paramagnetic.
4Step 4: Examine \\(\mathrm{Li}_{2}\\)
\(\mathrm{Li}_{2}\) has a total of 6 electrons. In its molecular orbital diagram, all electrons are paired, making \(\mathrm{Li}_{2}\) a diamagnetic molecule.
5Step 5: Examine \\(\mathrm{He}_{2}^{+}\\)
\(\mathrm{He}_{2}^{+}\) has 3 electrons. The molecular orbital configuration results in one unpaired electron in a \(\sigma_{1s}\) molecular orbital, indicating paramagnetism.
Key Concepts
Molecular Orbital TheoryParamagnetismElectron Pairing
Molecular Orbital Theory
Molecular Orbital (MO) Theory is a fundamental concept used to describe the electronic structure of molecules. It helps us understand how the atomic orbitals of bonding atoms combine to form molecular orbitals, which are spread over the entire molecule.
In essence, molecular orbitals can be thought of as the wave-like solutions to the Schrödinger equation for a molecule, similar to how atomic orbitals describe electrons in isolated atoms. These orbitals can be bonding, antibonding, or non-bonding:
In essence, molecular orbitals can be thought of as the wave-like solutions to the Schrödinger equation for a molecule, similar to how atomic orbitals describe electrons in isolated atoms. These orbitals can be bonding, antibonding, or non-bonding:
- Bonding Orbitals: These are lower in energy than the atomic orbitals that combined to form them, and they help stabilize the molecule.
- Antibonding Orbitals: These are higher in energy and can destabilize a molecule if occupied by electrons.
- Non-bonding Orbitals: These have energy equivalent to the atomic orbitals and do not contribute directly to bonding.
Paramagnetism
Paramagnetism occurs in substances with unpaired electrons. Unlike diamagnetic materials, which are repelled by magnetic fields, paramagnetic materials are attracted to magnetic fields.
This attraction is due to the unpaired electrons being able to align their spins with an external magnetic field. Here's what happens:
This attraction is due to the unpaired electrons being able to align their spins with an external magnetic field. Here's what happens:
- Unpaired Electrons: Electrons that are alone in an orbital contribute to magnetic properties due to their spin.
- Magnetic Alignment: These spins can line up with a magnetic field, enhancing the magnetic effect.
- Temporary Magnetization: The magnetism disappears once the external field is removed since the electron spins can return to random orientations.
Electron Pairing
Electron pairing is a foundational concept in chemistry that helps to explain the stability and reactivity of molecules. Electrons in atoms and molecules organize themselves to minimize energy, often pairing up in accordance with the Pauli Exclusion Principle.
In a given molecular orbital or atomic orbital, electrons prefer to pair their spins in opposite directions:
In a given molecular orbital or atomic orbital, electrons prefer to pair their spins in opposite directions:
- Spin Pairing: Each pair consists of one electron with a spin of +1/2 and another with a spin of -1/2. This pairing minimizes magnetic interactions.
- Increased Stability: Paired electrons contribute to a more stable energy state and can lead to diamagnetic properties when all electrons are paired in a molecule.
Other exercises in this chapter
Problem 68
Hydrogen bond is strongest in (a) \(\mathrm{S}-\mathrm{H}-\mathrm{O}\) (b) \(\mathrm{O}-\mathrm{H}-\mathrm{S}\) (c) \(\mathrm{F}-\mathrm{H}-\mathrm{F}\) (d) \(\
View solution Problem 69
Which of the following has the highest bond order? (a) \(\mathrm{N}_{2}\) (b) \(\mathrm{O}_{2}\) (c) \(\mathrm{He}_{2}\) (d) \(\mathrm{H}_{2}\)
View solution Problem 72
Iodine pentafluoride has which of the following hybridization? (a) \(\mathrm{d}^{2} \mathrm{sp}^{3}\) (b) \(\mathrm{dsp}^{3}\) (c) \(\mathrm{sp}^{3} \mathrm{~d}
View solution Problem 73
The number of lone pairs of electrons present in central atom of \(\mathrm{ClF}_{3}\) is (a) 0 (b) 1 (c) 2 (d) 3
View solution