Problem 70
Question
The identity of two different solid organic compounds having the same melting point can be best ascertained by determining their (a) dipole moment (b) solubility (c) melting point of their \(1: 1\) mixture (d) refractive indices
Step-by-Step Solution
Verified Answer
(c) Melting point of their 1:1 mixture is the best method for identification.
1Step 1: Understanding the Problem
We have two different solid organic compounds with the same melting point, and we must find the best method to ascertain their identities by distinguishing between them. The options given are dipole moment, solubility, melting point of their 1:1 mixture, and refractive indices.
2Step 2: Identifying Similarities and Differences
Since both compounds have the same melting point, measuring the melting point alone will not distinguish between them. Other properties like dipole moment, solubility, and refractive index could potentially differ based on the specific structure and molecular makeup of the compounds.
3Step 3: Analyzing the 1:1 Mixture
The melting point of a 1:1 mixture is a key technique known as a mixed melting point test. If two compounds are identical, the melting point of their mixture will remain the same. If they are different, the mixture will show a depressed and broader melting point range.
4Step 4: Choosing the Best Method
Among the given options, determining the melting point of their 1:1 mixture is the standard and most direct method to distinguish two different solid organic compounds with the same melting point. This method leverages the principle of melting point depression seen in mixtures.
Key Concepts
Melting Point AnalysisMixed Melting Point TestOrganic Compounds IdentificationPhysical Properties of Compounds
Melting Point Analysis
Melting point analysis is a fundamental technique in organic chemistry used to characterize solid organic compounds. This technique involves determining the temperature at which a solid turns into a liquid.
The melting point of a pure compound is a sharp, specific temperature, often used to verify the purity of a compound. Impurities usually lead to a depression and broadening of the melting point range.
By comparing the experimental melting point with known values, chemists can gain insights into the identity and purity of a compound. Melting point analysis is one of the simplest methods to ascertain the quality and authenticity of a compound in laboratory settings.
Mixed Melting Point Test
A mixed melting point test is a clever method used to identify two different compounds that have the same pure melting point.
To perform this test, equal parts of the two compounds are mixed and their melting point is measured.
- If the compounds are identical, the mixture will have a sharp melting point identical to the pure substances.
- If the compounds are different, the melting point of the mixture will be lower and will cover a broader temperature range.
Organic Compounds Identification
Identifying organic compounds is crucial in organic chemistry for both research and industry applications. Various techniques are used to determine the identity of compounds based on their physical and chemical properties.
Apart from melting point analysis, chemists may use
- infrared spectroscopy to assess functional groups,
- nuclear magnetic resonance (NMR) spectroscopy for molecular structure,
- mass spectrometry for molecular weight and composition.
Physical Properties of Compounds
The physical properties of organic compounds—such as melting point, boiling point, solubility, refractive index, and molecular weight—play a vital role in their identification and characterization.
These properties arise from the molecular structure and interactions between molecules, influencing how compounds behave in different environments.
- The boiling point and melting point provide clues about intermolecular forces.
- The solubility helps to understand interactions with different solvents.
- Refractive index measures how light passes through a substance, which can aid in distinguishing between compounds.
Other exercises in this chapter
Problem 68
If a compound on analysis was found to contain \(\mathrm{C}=\) \(18.5 \%, \mathrm{H}=1.55 \%, \mathrm{Cl}=55.04 \%\) and \(\mathrm{O}=24.81 \%\) then its empiri
View solution Problem 69
A compound with empirical formula \(\mathrm{CH}_{2} \mathrm{O}\) has a vapour density of 30 . Its molecular formula is (a) \(\mathrm{C}_{3} \mathrm{H}_{6} \math
View solution Problem 71
\(0.5 \mathrm{~g}\) of an organic compound in \(\mathrm{Kjeldahl}\) experiment needs \(29 \mathrm{ml}\) of \(\frac{\mathrm{N}}{5} \mathrm{H}_{2} \mathrm{SO}_{4}
View solution Problem 72
When thiourea is heated with metallic sodium, the compound which cannot be formed is (a) \(\mathrm{Na}_{2} \mathrm{SO}_{4}\) (b) \(\mathrm{Na}_{2} \mathrm{~S}\)
View solution