Problem 70
Question
The graph of \(y=x^{2}\) is said to be concave up. One way to define this property is as follows: If \(P=\left(a, a^{2}\right)\) and \(Q=\) \(\left(b, b^{2}\right)\) are any two points on the graph of \(y=x^{2},\) then the line segment \(\overline{P Q}\) lies above the graph of \(y=x^{2} .\) What is the equation of the line that passes through \(P\) and \(Q ?\) Algebraically verify that the midpoint of \(\overline{P Q}\) lies above the parabola.
Step-by-Step Solution
Verified Answer
Line equation: \(y = (b+a)x - a(b+a) + a^2\). Midpoint is above parabola as \(\frac{a^2 + b^2}{2} > \frac{(a+b)^2}{4}\).
1Step 1: Find the Slope of Line PQ
Given points \(P(a, a^2)\) and \(Q(b, b^2)\), the slope \(m\) of the line segment \(\overline{PQ}\) can be found using the formula for the slope: \[ m = \frac{b^2 - a^2}{b-a}. \]Expand this to get \( m = b+a \) since \( (b^2 - a^2) = (b-a)(b+a) \).
2Step 2: Define the Equation of Line PQ
The equation of a line in point-slope form is \(y - y_1 = m(x - x_1)\). Use point \(P(a, a^2)\) and slope \(b + a\):\[y - a^2 = (b + a)(x - a).\] Simplify to get the line equation:\[ y = (b + a)x - a(b + a) + a^2. \]
3Step 3: Find the Midpoint of PQ
The midpoint \(M\) of line segment \(\overline{PQ}\) is given by:\[ M\left( \frac{a+b}{2}, \frac{a^2+b^2}{2} \right). \]
4Step 4: Determine the y-coordinate of Midpoint M on Parabola
Substitute \(x = \frac{a+b}{2}\) into the equation of the parabola \(y = x^2\):\[ y = \left( \frac{a+b}{2} \right)^2 = \frac{(a+b)^2}{4}. \]
5Step 5: Compare Midpoint's y-coordinate with Parabola
Compute \( (a^2 + b^2)/2 \) and compare it with \( (a+b)^2/4 \):\[ \frac{a^2 + b^2}{2} \] and \[ \frac{(a+b)^2}{4} = \frac{a^2 + 2ab + b^2}{4}. \]Simplifying the comparison, \[ \frac{a^2 + b^2}{2} = \frac{2a^2 + 2b^2}{4} > \frac{a^2 + 2ab + b^2}{4}\] due to the positive term \(2ab\) implying the midpoint is above the parabola.
Key Concepts
Slope of a LineMidpoint FormulaParabolaPoint-Slope Form
Slope of a Line
The slope of a line is a measure of its steepness, describing how the line tilts from the horizontal axis. To find the slope between two points, you use their coordinates. Suppose we have two points, \(P(a, a^2)\) and \(Q(b, b^2)\) on a graph. The formula you will use to determine the slope \(m\) of the line that connects these two points is:
- \( m = \frac{b^2 - a^2}{b-a} \)
Midpoint Formula
Finding the midpoint between two points is like finding the average position between them on a line segment. It's calculated using their respective coordinates. For points \(P(a, a^2)\) and \(Q(b, b^2)\), the midpoint \(M\) is found using:
- \( M\left( \frac{a+b}{2}, \frac{a^2+b^2}{2} \right) \)
Parabola
A parabola is a U-shaped curve on a graph described by a quadratic equation like \(y = x^2\). It is remarkably symmetric, centered around a vertical line called the axis of symmetry. Parabolas can either open upwards or downwards depending on the coefficient of \(x^2\). For \(y = x^2\), the parabola is said to be "concave up" as it hollowly faces upwards.
- The turning point is its vertex, located at the origin \((0,0)\) for \(y = x^2\).
- As \(x\) values increase positively or negatively, the \(y\) always increases, signifying uplift.
- The parabola's shape and position can be affected by changing coefficients and constants.
Point-Slope Form
The point-slope form is a common method for writing the equation of a line, especially when you know the slope of a line and a point on it. The general form is given by:
- \(y - y_1 = m(x - x_1)\)
- \(y - a^2 = (b + a)(x - a)\)
Other exercises in this chapter
Problem 70
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