Problem 70
Question
Suppose that the graph of \(y=x^{2}\) is translated in such a way that its domain is \((-\infty, \infty)\) and its range is \([38, \infty)\). What values of \(h\) and \(k\) can be used if the new function is of the form \(y=(x-h)^{2}+k ?\) (Graph cannot copy)
Step-by-Step Solution
Verified Answer
The values are \(h = 0\) and \(k = 38\).
1Step 1: Understanding Translations
When a graph of a function is translated, its basic shape doesn't change, but its position does. For the function \(y = x^2\), a translation can be vertical, represented by \( y = x^2 + k \), or horizontal, represented by \( y = (x-h)^2 \). Here, the translation results in a new range \([38, \infty)\).
2Step 2: Analyzing the Vertex Change
The vertex of the function \(y = x^2\) is at \((0, 0)\), and the range is \([0, \infty)\). We need the range to be \([38, \infty)\), indicating the vertex must shift up to \( (h, k) = (0, 38)\). This means the function is vertically translated \(38\) units upward.
3Step 3: Identifying Translation Parameters
The horizontal translation \(h\) doesn't affect the range but only shifts the graph horizontally. Since there's no stipulation for changing the domain or horizontal shift in the problem, \(h\) remains \(0\). The achieved range by vertical shift confirms \(k = 38\).
4Step 4: Writing the Translated Function
The function considering the translations is \(y = (x-0)^2 + 38 \), which simplifies to \(y = x^2 + 38\). This new function correctly translates the vertex and adjusts the range appropriately.
Key Concepts
Understanding Quadratic FunctionsExploring Vertex Shifts in Quadratic FunctionsUnderstanding the Range of a Quadratic Function
Understanding Quadratic Functions
Quadratic functions are a fundamental concept in algebra and they are typically represented by the equation \( y = ax^2 + bx + c \). When we talk about quadratic functions, the most basic form and the one most frequently examined is \( y = x^2 \). This form represents a parabola that opens upward with its vertex at the origin \( (0, 0) \).
Quintessential features of quadratic functions include:
Quintessential features of quadratic functions include:
- Vertex: The highest or lowest point of the parabola, depending on whether it opens upward or downward.
- Axis of symmetry: A vertical line that passes through the vertex and divides the parabola into two mirror-image halves.
- Opening direction: Determined by the coefficient \( a \). If \( a > 0 \), the parabola opens upward; if \( a < 0 \), it opens downward.
- Transformations: Include shifting, reflecting, stretching, and compressing the graph, usually involving changes to coefficients in the function's equation.
Exploring Vertex Shifts in Quadratic Functions
A vertex shift refers to the movement of the vertex of a quadratic function's graph, typically described by changes in parameters \( h \) and \( k \) in the vertex form equation \( y = (x-h)^2 + k \).
Here, the variable \( h \) dictates the horizontal shift, while \( k \) dictates the vertical shift. When the vertex of the standard parabola \( y = x^2 \) moves to a new position, both the horizontal and vertical location of the parabola also change.
Here, the variable \( h \) dictates the horizontal shift, while \( k \) dictates the vertical shift. When the vertex of the standard parabola \( y = x^2 \) moves to a new position, both the horizontal and vertical location of the parabola also change.
- Vertical Shifts: If \( k > 0 \), the parabola shifts up; if \( k < 0 \), it shifts down, changing the range accordingly.
- Horizontal Shifts: Adjustments in \( h \) translate the graph left or right. Specifically, \( (x-h) \) shifts right if \( h > 0 \) and left if \( h < 0 \).
Understanding the Range of a Quadratic Function
The range of a function is the set of all possible output values. For a basic quadratic function \( y = x^2 \), the range is \([0, \infty)\), because the smallest value \( y \) can take is 0, increasing as \( x \) moves away from the origin in either direction.
When we translate a parabola vertically, as seen with our function \( y = x^2 + 38 \), the whole graph shifts up by 38 units adjusting the minimum point of the parabola.
Thus:
When we translate a parabola vertically, as seen with our function \( y = x^2 + 38 \), the whole graph shifts up by 38 units adjusting the minimum point of the parabola.
Thus:
- The new range becomes \([38, \infty)\).
- This upward translation doesn't affect the domain, which remains as \(( -\infty, \infty )\).
Other exercises in this chapter
Problem 70
Each function is either even or odd Evaluate \(f(-x)\) to determine which situation applies. $$f(x)=4 x-\frac{1}{x}$$
View solution Problem 70
Solve each equation or inequality. $$|4-3 x|>1$$
View solution Problem 70
Let the domain of \(f(x)\) be [-1,2] and the range be \([0,3] .\) Find the domain and range of the following. $$5 f(x+1)$$
View solution Problem 71
Each function is either even or odd Evaluate \(f(-x)\) to determine which situation applies. $$f(x)=\frac{x^{3}+3 x}{x}$$
View solution