Problem 70
Question
Solve the system of equations by elimination. $$ \begin{array}{l} 4 x-y=12 \\ 4 x-y=24 \end{array} $$ Solution: Multiply Equation ( 1 ) by -1 Add the result to Equation (2) $$\begin{array}{rr} -4 x+y= & -12 \\ -4 x+y= & -12 \\ 4 x-y= & 24 \\ \hline 0= & 12 \end{array}$$ Answer: Infinitely many solutions. This is incorrect. What mistake was made?
Step-by-Step Solution
Verified Answer
The system has no solutions because the equations are inconsistent.
1Step 1: Identify the Equations
We have the system of equations: \( 4x - y = 12 \) and \( 4x - y = 24 \). These equations are written in the form \( Ax + By = C \).
2Step 2: Compare the Equations
Look at the coefficients of \(x\) and \(y\). Both equations have the same coefficients: 4 for \(x\) and -1 for \(y\). However, the constant terms (12 and 24) are different.
3Step 3: Analyze the System
Since the left-hand sides of the equations are identical (i.e., they have the same coefficients for \(x\) and \(y\)), but the right-hand sides (the constants) are different, the system is inconsistent. This means it has no solution.
4Step 4: Recognize the Error
The error in the original solution was asserting that the system has infinitely many solutions. In reality, the system of equations has no possible values for \(x\) and \(y\) that satisfy both equations simultaneously because the left-hand sides are identical but yield different results (12 and 24).
Key Concepts
Elimination MethodInconsistent SystemSolution Analysis
Elimination Method
The elimination method is one of the primary techniques used to solve systems of equations. It's particularly useful when you want to eliminate one of the variables so you can solve for the other. Here’s a breakdown of how it works:
- Align the Equations: Start by writing the system of equations in a standard form, usually as \(Ax + By = C\). This helps in comparing the coefficients of the variables.
- Make the Coefficients Opposite: Manipulate the equations so that you can eliminate one variable. This often involves multiplying one or both equations by a specific number that makes the coefficients of one variable equal and opposite.
- Add or Subtract the Equations: Use addition or subtraction to cancel one of the variables out. This results in a single equation with one variable, which can then be solved to find a particular value.
Inconsistent System
An inconsistent system of equations occurs when there are no simultaneous solutions for the variables that can satisfy both equations. This can happen due to contradictory information presented by the equations.
- Identical Coefficients, Different Constants: If two equations have the same coefficients for the variables, but different constants on the right side, this indicates inconsistency. It means that the equations describe parallel lines that will never intersect, hence no solution exists.
- Graphical Interpretation: On a graph, an inconsistent system generally translates to parallel lines that have no point in common.
Solution Analysis
When analyzing a system of equations, recognizing the type of solution is crucial. There are three potential outcomes for a system: exactly one solution, no solution, or infinitely many solutions.
- Exactly One Solution: This occurs when the system of equations represents two lines that intersect at a single point. The coefficients and constants differ, supporting a unique intersection point.
- No Solution: Known as an inconsistent system, this happens when the equations describe parallel lines that never meet. Our exercise falls under this category, where identical left-hand sides but differing constants point to parallel lines.
- Infinitely Many Solutions: This happens when the equations are essentially the same, i.e., multiples of each other, leading to coinciding lines that overlap completely.
Other exercises in this chapter
Problem 70
apply matrix algebra to solve the system of linear equations. $$\begin{aligned}&x+2 y-3 z=1\\\&x-y-z=3\\\&x \quad-4 z=0\end{aligned}$$
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Solve the system of linear equations. $$ \begin{array}{r} 2 x+3 y=6 \\ -x-y=-3 \end{array} $$ Solution: Set up the determinants. $$ D=\left|\begin{array}{rr} 2
View solution Problem 71
apply matrix algebra to solve the system of linear equations. $$\begin{array}{rr}2 x+4 y+z= & -5 \\\x+y-z= & 7 \\\x+y= & 0\end{array}$$
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