Problem 70
Question
Solve each inequality in Exercises 57-84 by first rewriting each one as an equivalent inequality without absolute value bars. Graph the solution set on a number line. Express the solution set using interval notation. $$|x+3| \geq 4$$
Step-by-Step Solution
Verified Answer
The solution set to the inequality \(|x + 3| \geq 4\) is \([-7, -\infty) \cup [1, \infty)\].
1Step 1: Rewrite the inequality without absolute value bars
An absolute value inequality \(|x+a| \geq b\) can be rewritten as \(x + a \geq b\) or \(x + a \leq -b\). Applying this to our exercise, we get two separate inequalities \(x + 3 \geq 4\) and \(x + 3 \leq -4\).
2Step 2: Solve each inequality separately
To solve the first inequality \(x + 3 \geq 4\), we subtract 3 from both sides to find \(x \geq 1\). To solve the second inequality \(x + 3 \leq -4\), we subtract 3 from both sides to find \(x \leq -7\).
3Step 3: Graph the solution
Draw a real number line. Here, we shall illustrate two segments. The first one is from 1 (inclusive) to positive infinity, accompanied by a arrow depicting continuity till infinity. The other segment is from -7 (inclusive) to negative infinity. Thus demonstrating that the value of 'x' can lie in either of these two segments.
4Step 4: Express the solution in interval notation
The solution is expressed in interval notation as \([-7, -\infty) \cup [1, \infty)\].
Key Concepts
Interval NotationNumber Line GraphingInequality SolvingEquivalent Inequalities
Interval Notation
Interval notation is a concise way of describing a set of numbers along a number line. It uses brackets and parentheses to convey inclusivity and exclusivity of endpoints. To express a solution set in interval notation, we use the following rules:
- If the endpoint number is included in the set, we use square brackets [ ].
- If the endpoint is not included, we use round brackets ( ).
\([-7, -\infty) \cup [1, \infty)\). Here, the square bracket on -7 means -7 is part of the solution set, while the parenthesis with infinity signifies that the set extends indefinitely. The union symbol \(\cup\) indicates that the values of \(x\) can be in either of these intervals.Number Line Graphing
Graphing solutions on a number line is a visual way to represent the range of solutions. To graph the solution set for an inequality, follow these steps:
- Draw a horizontal line and mark numbers on it, like -7 and 1, according to the problem's context.
- Use solid dots or closed circles to denote endpoints included in the solution set. For example, at points -7 and 1.
- Draw an arrow extending into infinity to show continuity. In this example, there would be one arrow pointing left from -7 and another pointing right from 1.
Inequality Solving
Solving inequalities involves finding the values of the variable that satisfy the given condition. For absolute value inequalities, like
|x + 3| \geq 4, we rewrite to remove the absolute value by creating two separate inequalities:- First inequality: \(x + 3 \geq 4\)
- Second inequality: \(x + 3 \leq -4\)
Equivalent Inequalities
Equivalent inequalities are different expressions that represent the same solutions in terms of the set of numbers that satisfy them. When rewriting absolute value inequalities such as
|x + 3| \geq 4, we establish two new inequalities:- \(x + 3 \geq 4\) representing values above a certain point.
- \(x + 3 \leq -4\) representing values below a certain point.
Other exercises in this chapter
Problem 70
Solve each absolute value equation or indicate the equation has no solution. $$ |x+1|+6=2 $$
View solution Problem 70
In Exercises \(57-76,\) solve each formula for the specified variable. Do you recognize the formula? If so, what does it describe? \(S=P+P r t\) for \(t\)
View solution Problem 70
The equations in Exercises \(59-70\) combine the types of equations we have discussed in this section. Solve each equation or state that it is true for all real
View solution Problem 71
Compute the discriminant of each equation in Exercises 65-72 What does the discriminant indicate about the number and type of solutions? \(x^{2}-3 x-7=0\)
View solution