Problem 70
Question
Should help you pull together all of the factoring techniques of this chapter. Factor completely each polynomial, and indicate any that are not factorable using integers. $$5 x^{2}+42 x-27$$
Step-by-Step Solution
Verified Answer
The polynomial is completely factored as \((5x - 3)(x + 9)\).
1Step 1: Examine the Polynomial
The polynomial we are given is of the form \( ax^2 + bx + c \), where \( a = 5 \), \( b = 42 \), and \( c = -27 \). We need to factor this quadratic polynomial completely or determine that it is not factorable with integers.
2Step 2: Check for a Common Factor
First, let's check if there is a common factor for all terms in the polynomial. The coefficients 5, 42, and -27 have no common factor other than 1, so we cannot factor any common numbers out of the polynomial.
3Step 3: Identify Factorization Technique
Since there is no common factor, we can use factoring techniques such as the AC method to factor the quadratic. The AC method involves finding two numbers that multiply to \( a \times c = 5 \times (-27) = -135 \) and add up to \( b = 42 \).
4Step 4: Use AC Method
We need two numbers, \( m \) and \( n \), such that \( m \times n = -135 \) and \( m + n = 42 \). After testing several factor pairs of -135, we find that \( m = 45 \) and \( n = -3 \) satisfy both conditions.
5Step 5: Rewrite the Middle Term
Now, we can rewrite the polynomial as \( 5x^2 + 45x - 3x - 27 \). This helps us to factor by grouping.
6Step 6: Factor by Grouping
Group the terms: \( (5x^2 + 45x) + (-3x - 27) \). Factor out the greatest common factor from each group: \( 5x(x + 9) - 3(x + 9) \).
7Step 7: Complete the Factorization
Notice \( (x + 9) \) is a common factor, so factor it out: \( (5x - 3)(x + 9) \).
8Step 8: Check the Factorization
Expand \( (5x - 3)(x + 9) \) to ensure it gives the original polynomial: \( 5x^2 + 45x - 3x - 27 = 5x^2 + 42x - 27 \), confirming the factorization is correct.
Key Concepts
Quadratic PolynomialsFactoring TechniquesAC Method
Quadratic Polynomials
Quadratic polynomials are expressions of the form \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants and \( a eq 0 \). These polynomials represent parabolic curves when graphed on a coordinate plane. The highest power of the variable \( x \) in such expressions is 2, hence the term "quadratic."
The standard form \( ax^2 + bx + c \) is essential because it forms the basis for many operations in algebra, especially factoring.
Understanding the components of a quadratic polynomial helps in determining its roots, analyzing its graph, and solving equations. Each term has a specific function:
The standard form \( ax^2 + bx + c \) is essential because it forms the basis for many operations in algebra, especially factoring.
Understanding the components of a quadratic polynomial helps in determining its roots, analyzing its graph, and solving equations. Each term has a specific function:
- The \( ax^2 \) term dictates the parabola's direction and width.
- The \( bx \) term affects the orientation and axis of symmetry.
- The constant \( c \) shows where the parabola crosses the y-axis.
Factoring Techniques
Factoring techniques for polynomials involve breaking down a complicated expression into factors. These factors are expressions that, when multiplied together, give the original polynomial.
Factoring is useful because it simplifies calculations and reveals polynomial roots.
Factoring is useful because it simplifies calculations and reveals polynomial roots.
- Common Factor: Check for a number or variable that divides all terms. If present, factor it out first. This simplifies the polynomial and can make further factoring easier.
- Factoring Quadratics: Often involves finding two numbers that multiply to \( ac \) (when the polynomial is written as \( ax^2 + bx + c \)) and add to \( b \). This is vital for techniques like the AC method.
- Group Factoring: Break the expression into groups that share a common factor. Then, factor each group and find remaining common factors.
AC Method
The AC method is a systematic approach to factoring quadratics by considering the product of the coefficient of \( x^2 \), \( a \), and the constant term, \( c \). The method is particularly useful when \( a eq 1 \) and there is no common factor.
The idea is to multiply \( a \) and \( c \) to get the product \( ac \), find two numbers whose product equals \( ac \) and whose sum equals the middle coefficient \( b \).
Steps for the AC method include:
Steps for the AC method include:
- Compute \( ac \) by multiplying the leading coefficient \( a \) and the constant \( c \).
- Identify two numbers, \( m \) and \( n \), such that \( m \times n = ac \) and \( m + n = b \).
- Rewrite the middle term \( bx \) as \( mx + nx \) based on the values found.
- Factor by grouping, isolating the common factor in each part.
- Extract the common binomial factor to complete the factorization.
Other exercises in this chapter
Problem 69
Find each quotient. $$\frac{-72 x^{2} y^{4}}{-8 x^{2} y^{4}}$$
View solution Problem 69
Simplify by removing the inner parentheses first and working outward. $$\left[4 x^{3}-\left(2 x^{2}-x-1\right)\right]-\left[5 x^{3}-\left(x^{2}+2 x-1\right)\rig
View solution Problem 70
Find all real number solutions for each equation. $$4 x^{3}+12 x=0$$
View solution Problem 70
Solve each of the equations. $$b^{2}=-7 b$$
View solution