Problem 70
Question
In Exercises \(67-70\) , use a CAS to estimate the magnitude of the error in using the linearization in place of the function over a specified interval \(I\) . Perform the following steps: a. Plot the function \(f\) over \(I .\) b. Find the linearization \(L\) of the function at the point \(a\) . c. Plot \(f\) and \(L\) together on a single graph. d. Plot the absolute error \(|f(x)-L(x)|\) over \(I\) and find its maximum value. e. From your graph in part (d), estimate as large a \(\delta > 0\) as you can, satisfying $$ |x-a|<\delta \quad \Rightarrow \quad|f(x)-L(x)|<\epsilon $$ for \(\epsilon=0.5,0.1,\) and 0.01 . Then check graphically to see if your \(\delta\) -estimate holds true. $$ f(x)=\sqrt{x}-\sin x, \quad[0,2 \pi], \quad a=2 $$
Step-by-Step Solution
VerifiedKey Concepts
Linearization
- \( L(x) = f(a) + f'(a)(x - a) \)
Error estimation
In this context, we use the absolute error, which quantifies the estimation error as:
- \( |f(x) - L(x)| \)
Absolute error
- \( |f(x) - L(x)| \)
Detecting the maximum absolute error within a given interval allows us to quantify the worst-case scenario deviation when using the linearization instead of the original function. Having this information empowers individuals to determine the usability of the approximation for practical applications, thus improving decision-making.
Derivative
The derivative, when evaluated at a specific point \( a \), gives us the slope of the tangent line to the function at that point. In the case of the given exercise, for a function \( f(x) = \sqrt{x} - \sin x \), the derivative \( f'(x) \) is:
- \( f'(x) = \frac{1}{2\sqrt{x}} - \cos x \)