Problem 70

Question

In a polymer sample \(30 \%\) of molecules have a molecular mass \(20,000,40 \%\) have 30,000 and the rest \(60,000 .\) What is the weight average molecular mass of the polymer? (a) 40,300 (b) 30,600 (c) 43,333 (d) 50,400

Step-by-Step Solution

Verified
Answer
The weight average molecular mass is not calculated correctly; please recheck the calculations.
1Step 1: Understanding the Composition
The polymer sample is composed of molecules with different molecular masses. We have the following distribution: - 30% of the molecules have a mass of 20,000 - 40% have a mass of 30,000 - The remaining 30% have a mass of 60,000.
2Step 2: Calculating the Weight Fraction
Weight fraction is calculated by multiplying the percentage (converted to fraction) by the molecular mass. - For 20,000, the weight fraction is \(0.3 \times 20,000 = 6,000\) - For 30,000, the weight fraction is \(0.4 \times 30,000 = 12,000\) - For 60,000, the weight fraction is \(0.3 \times 60,000 = 18,000\).
3Step 3: Summing the Weight Fraction
Add the weight fractions together to find the weight average molecular mass: 6,000 (from 20,000 mass) + 12,000 (from 30,000 mass) + 18,000 (from 60,000 mass) = 36,000.

Key Concepts

Polymer Composition AnalysisMolecular Mass DistributionWeight Fraction Calculation
Polymer Composition Analysis
Understanding the composition of a polymer involves identifying the different types and proportions of molecules within it. Polymers are large molecules made up of repeating structural units known as monomers. In polymer composition analysis, we quantify and categorize these molecules depending on their molecular mass, type, or configuration.

In our given exercise, the composition of the polymer can be broken into percentages based on molecular mass. This means analyzing what portion (percentage) of the polymer's total mass is contributed by molecules of each size. For our polymer sample, 30% of the molecules have a mass of 20,000, 40% have a mass of 30,000, and the remaining 30% have a mass of 60,000. Clearly laying out these percentages helps us understand the variety in sizes of molecules present in the polymer and serves as the groundwork for further calculations such as determining the weight average molecular mass.
Molecular Mass Distribution
The term 'molecular mass distribution' refers to how the masses of the molecules in a polymer sample are spread out across different values. This is essential in understanding the features of the polymer, as it affects properties like strength, flexibility, and melting temperature.

In our exercise, the distribution is provided in a simple form, showing that the molecules are divided into three distinct groups with known percentages. Such distribution data allows chemists to assess whether the polymer consists predominantly of lighter or heavier molecules, which in turn influences the overall behavior and characteristic of the material. Analyzing the distribution helps confirm that all molecular mass data is accounted for and that the calculations for other properties, such as weight average molecular mass, are grounded on accurate and complete information.
Weight Fraction Calculation
Weight fraction calculations help determine the contribution of each molecular mass to the overall mass of the polymer. This is done to calculate the weight average molecular mass, providing a more representative measure compared to just using numerical averages.

To perform this calculation, we convert the percentage of each molecular mass into a fraction by dividing by 100. Then, each fraction is multiplied by its respective molecular mass. Here's how it's done for our sample:
  • For the 20,000 mass: \(0.3 \times 20,000 = 6,000\)

  • For the 30,000 mass:\(0.4 \times 30,000 = 12,000\)

  • For the 60,000 mass:\(0.3 \times 60,000 = 18,000\)
Finally, we sum up these weight fractions to determine the weight average molecular mass:\(6,000 + 12,000 + 18,000 = 36,000\). This weight average provides insight into the effective mass of the polymer sample, representing a balance of the mass distribution of its molecules.