Problem 70
Question
Give the focus, directrix, and axis of each parabola. $$x^{2}=\frac{1}{9} y$$
Step-by-Step Solution
Verified Answer
Focus: \((0, \frac{1}{36})\), Directrix: \(y = -\frac{1}{36}\), Axis: \(x = 0\).
1Step 1: Identify the Parabola's Orientation
The given equation is \(x^2 = \frac{1}{9}y\), which is in the form of \(x^2 = 4py\). This indicates that the parabola opens either upwards or downwards.
2Step 2: Find the Value of \(p\)
The standard form equation \(x^2 = 4py\) helps us find \(p\) by comparing with \(x^2 = \frac{1}{9}y\). Comparing both equations, we have \(4p = \frac{1}{9}\). Solving for \(p\), we get \(p = \frac{1}{36}\).
3Step 3: Determine the Focus
For a parabola in the form \(x^2 = 4py\) with the vertex at the origin, the focus is at \((0, p)\). Thus, with \(p = \frac{1}{36}\), the focus is located at \(\left(0, \frac{1}{36}\right)\).
4Step 4: Determine the Directrix
The directrix of a parabola \(x^2 = 4py\) is a line given by \(y = -p\) if the parabola opens upwards. Thus, the directrix is \(y = -\frac{1}{36}\).
5Step 5: Identify the Axis of Symmetry
The axis of symmetry for parabolas of the form \(x^2 = 4py\) is the \(y\)-axis, which means the equation of the axis is \(x = 0\).
Key Concepts
Focus of a ParabolaDirectrix of a ParabolaAxis of Symmetry
Focus of a Parabola
The focus of a parabola holds a vital spot in understanding its structure. Think of the focus as a special point within the curve. All points on a parabola are equidistant from the focus and the directrix. For the given parabola equation, \(x^2 = \frac{1}{9}y\), its focus can be located using the equation, \(x^2 = 4py\). This standard form helps us determine \(p\), the distance from the vertex to the focus.
- First, identify \(4p\) in the equation, which corresponds to \(\frac{1}{9}\).
- When you solve for \(p\), you find \(p = \frac{1}{36}\).
- This means that the focus is at point \((0, \frac{1}{36})\).
Directrix of a Parabola
The directrix of a parabola is like a guide line that runs parallel to the parabola's orientation. It's not part of the parabola itself but serves as a geometrical reference used to define the curve.
- For the equation \(x^2 = \frac{1}{9}y\), this line is horizontal because the parabola opens upwards.
- The directrix is determined by the formula \(y = -p\).
- With \(p = \frac{1}{36}\), the directrix becomes \(y = -\frac{1}{36}\).
Axis of Symmetry
The axis of symmetry is a line of perfect balance for parabolas, defining how they reflect around a central line. For a parabola in the form \(x^2 = 4py\), this axis is vertical.
- It runs through the vertex and every point along this axis reflects onto the opposite side of the parabola.
- In our given equation, the axis of symmetry is represented by \(x = 0\).
Other exercises in this chapter
Problem 69
Solve each nonlinear system of equations analytically for all real solutions. $$\begin{aligned} &2 x^{2}+2 y^{2}=20\\\ &3 x^{2}+3 y^{2}=30 \end{aligned}$$
View solution Problem 70
Find an equation for each hyperbola. Vertices \((0,5)\) and \((0,-5) ;\) passing through \((3,10)\)
View solution Problem 70
Solve each nonlinear system of equations analytically for all real solutions. $$\begin{aligned} x^{2}+y^{2} &=4 \\ 5 x^{2}+5 y^{2} &=28 \end{aligned}$$
View solution Problem 71
Find an equation for each hyperbola. Foci ( \(0, \sqrt{13}\) ) and ( \(0,-\sqrt{13}\) ); asymptotes \(y=\pm 5 x\)
View solution