Problem 70
Question
For the following exercises, use the written statements to construct a polynomial function that represents the required information. A rectangle is twice as long as it is wide. Squares of side 2 feet are cut out from each corner. Then the sides are folded up to make an open box. Express the volume of the box as a function of the width \((x)\).
Step-by-Step Solution
Verified Answer
The volume function is \(V(x) = 4x^2 - 32x + 32\).
1Step 1: Understanding the problem
We first need to understand the geometry of the open box. The rectangle is described as having a length twice its width, so if the width is \(x\), the length will be \(2x\). Squares with a side of 2 feet are cut from each corner, reducing both the length and width by 4 feet each.
2Step 2: Defining dimensions
After the squares are cut out and the sides folded up, the new dimensions of the base of the box become: width: \(x - 4\) and length: \(2x - 4\). The height of the box is the side of the square cut out, which is 2 feet.
3Step 3: Constructing the Volume Formula
The volume \(V\) of the box can be expressed as the product of its length \(2x-4\), width \(x-4\), and height 2 (from the squares cut out). Hence, the volume function is given by, \[ V(x) = (2x-4)(x-4)(2) \].
4Step 4: Simplifying the Volume Formula
Now we simplify the expression: \[ V(x) = 2(x-4)(2x-4) \]. Distributing the terms, first expand \((x-4)(2x-4)\): \((x \cdot 2x) - (x \cdot 4) - (4 \cdot 2x) + (4 \cdot 4) = 2x^2 - 8x - 8x + 16\), which simplifies to \(2x^2 - 16x + 16\). Finally, multiply by 2: \(V(x) = 2(2x^2 - 16x + 16) = 4x^2 - 32x + 32\).
Key Concepts
Volume CalculationAlgebraic ExpressionsGeometry Problems
Volume Calculation
Volume calculation is an essential concept in geometry and algebra. It helps us determine the amount of space an object occupies. In the context of a box created from a rectangle, understanding how to find its volume becomes practical and straightforward. When shaping the box, we begin by cutting out squares from each corner of the rectangle and folding up the sides to form an open top box. The primary formula for volume is the product of the base area and height. Here, the base area is derived from the modified dimensions after squares are removed:
- Width: \( x - 4 \)
- Length: \( 2x - 4 \)
- Height (from the cut squares): 2 feet
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and arithmetic operations used to represent real-world problems. In the context of the problem, the volume of the box is represented as a polynomial function of \(x\). This polynomial function, \(V(x) = 4x^2 - 32x + 32\), describes the volume in terms of the box's width, which allows us to compute the volume for various widths quickly. Working with algebraic expressions involves:
- Identifying the variables (here, \(x\) as the width of the rectangle).
- Understanding how changes in \(x\) affect the output (volume).
- Simplifying expressions step-by-step by distributing, combining like terms, and factoring.
Geometry Problems
Geometry problems often involve analyzing shapes and their properties, a skill that's particularly evident in constructing our box from a rectangle. Such problems link algebra with physical space, helping us visualize dimensions and transformations. For this problem, the rectangle transforms into an open box. Key steps include:
- Understanding proportional relationships: the rectangle's length is twice its width (\(2x\)).
- Visualizing structural changes by removing equal-sized squares from corners to change the shape.
- Applying geometric principles to identify new dimensions after modifications – reducing both length and width by twice the square's side.
Other exercises in this chapter
Problem 70
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