Problem 70
Question
Explain why the reaction of calcium and fluorine does not form CaF \(_{3}\).
Step-by-Step Solution
Verified Answer
Calcium forms CaF_{2} by bonding with two fluorine atoms, maintaining charge neutrality.
1Step 1: Understanding Chemical Bonds
Calcium is an alkaline earth metal, which belongs to Group 2 of the periodic table and forms bonds by losing electrons. Fluorine is a halogen, belonging to Group 17, and forms bonds by gaining electrons. The formation of chemical compounds involves the transfer or sharing of electrons to achieve a stable electron configuration.
2Step 2: Determining Valency
Calcium has two valence electrons and typically loses these two electrons to achieve a noble gas electron configuration, forming a +2 charge ion (Ca^{2+}). Fluorine has seven valence electrons and requires one more electron to achieve a stable configuration, gaining an electron to form a -1 charge ion (F^-).
3Step 3: Matching Charges for Compound Formation
In typical ionic compounds, the sum of the charges of the ions should equal zero for the compound to be neutral. Therefore, one calcium ion (Ca^{2+}) can bond with two fluoride ions (F^-) to form a neutral compound. This leads to the formation of calcium fluoride (CaF_{2}), rather than CaF_{3}.
4Step 4: Validating Neutral Compound
If CaF_{3} were to form, it would violate the rule of charge neutrality. A compound of Ca with three F^- would result in a net charge of -1 (Ca^{2+} + 3 * F^- = +2 + 3*(-1) = -1), which is not permissible. Hence, the correct chemical formula for the compound of calcium and fluorine is CaF_{2}.
Key Concepts
Ionic CompoundsElectron ConfigurationValency
Ionic Compounds
Ionic compounds are formed when atoms transfer electrons to achieve a full outer shell, creating charged particles called ions. These ions have opposite charges and attract each other, forming a stable structure known as an ionic bond.
For instance, in the case of calcium and fluorine, calcium loses electrons to become positively charged, while fluorine gains electrons to become negatively charged. This mutual electron transfer enables them to bind together.
For instance, in the case of calcium and fluorine, calcium loses electrons to become positively charged, while fluorine gains electrons to become negatively charged. This mutual electron transfer enables them to bind together.
- Structure: Typically, ionic compounds form a repeating pattern of ions called a crystal lattice, which is very stable.
- Properties: Ionic compounds generally have high melting and boiling points due to strong ionic bonds. They also tend to be soluble in water and conduct electricity when dissolved or molten.
Electron Configuration
Electron configuration is the arrangement of electrons around an atom's nucleus, crucial for understanding how elements bond chemically. Atoms tend to achieve a stable electron configuration similar to that of noble gases, which have a full outer shell.
Calcium has an electron configuration of [Ar] 4s², with two electrons in its outer shell that it can lose to stabilize. On the other hand, fluorine's configuration is [He] 2s² 2p⁵, just one electron short of a full shell.
Calcium has an electron configuration of [Ar] 4s², with two electrons in its outer shell that it can lose to stabilize. On the other hand, fluorine's configuration is [He] 2s² 2p⁵, just one electron short of a full shell.
- When calcium reacts with fluorine, it loses its two outer electrons, adopting the configuration of argon, a noble gas.
- Fluorine gains one electron to complete its outer shell, mimicking the configuration of neon.
Valency
Valency describes an atom's ability to bond with other atoms, determined by the number of electrons it can lose, gain, or share. In any bonding situation, matching valency ensures that the compound formed is stable and neutral.
For calcium, the valency is +2, reflecting its capacity to lose two electrons. Meanwhile, fluorine, with a valency of -1, needs only one electron to achieve stability. This difference in valency is key in predicting how many atoms of each type will be involved in forming a stable compound.
In our previous example:
For calcium, the valency is +2, reflecting its capacity to lose two electrons. Meanwhile, fluorine, with a valency of -1, needs only one electron to achieve stability. This difference in valency is key in predicting how many atoms of each type will be involved in forming a stable compound.
In our previous example:
- One calcium ion ( ext{Ca}^{2+}) will bond with two fluoride ions ( ext{F}^-), matching their combined negative charge to calcium's positive charge.
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