Problem 70
Question
Exer. 67-70: The formula specifies the position of a point \(P\) that is moving harmonically on a vertical axis, where \(t\) is in seconds and \(d\) is in centimeters. Determine the amplitude, period, and frequency, and describe the motion of the point during one complete oscillation (starting at \(t=0\) ). $$ d=6 \sin \frac{2 \pi}{3} t $$
Step-by-Step Solution
Verified Answer
Amplitude: 6 cm, Period: 3 s, Frequency: 1/3 Hz; the point oscillates vertically between +6 cm and -6 cm.
1Step 1: Identifying the Equation and Components
The given equation for the motion of the point is \( d = 6 \sin \left( \frac{2\pi}{3} t \right) \). Here, \(6\) is the amplitude, \(\frac{2\pi}{3}\) is the angular frequency \(\omega\), and \(t\) is the time.
2Step 2: Calculating the Amplitude
The amplitude of the motion is the coefficient of the sine function in the equation. Here, the amplitude is \(6\) centimeters.
3Step 3: Determining the Period
The period \(T\) of the motion is determined by the formula \(T = \frac{2\pi}{\omega}\). Substitute \(\omega = \frac{2\pi}{3}\) to find \(T = \frac{2\pi}{\frac{2\pi}{3}} = 3\) seconds.
4Step 4: Finding the Frequency
The frequency \(f\) is the reciprocal of the period, calculated by \(f = \frac{1}{T}\). With \(T = 3\) seconds, the frequency is \(f = \frac{1}{3}\) Hz.
5Step 5: Describing the Motion for One Complete Oscillation
In one complete oscillation starting at \(t=0\), the point moves from the equilibrium position \(d=0\) up to \(d=6\), back through \(d=0\), down to \(d=-6\), and returns to \(d=0\). This motion completes within 3 seconds, moving harmonically.
Key Concepts
AmplitudePeriodFrequencySine Function
Amplitude
When discussing harmonic motion, amplitude is a key component. In simple terms, amplitude refers to how far a point moves from its resting or equilibrium position. Imagine it as the height of a wave from its center line. In the given equation \( d = 6 \sin \frac{2\pi}{3} t \), the amplitude is represented by the number before the sine function, which is 6 centimeters. This means that the point \( P \) will move 6 centimeters above and below the equilibrium position during its motion.
Amplitude is vital because it tells us the maximum extent of the motion. Unlike other aspects such as frequency or period, amplitude is solely about the distance covered during this motion.
Amplitude is vital because it tells us the maximum extent of the motion. Unlike other aspects such as frequency or period, amplitude is solely about the distance covered during this motion.
- Maximum displacement: 6 cm
- Measured from the equilibrium position
- Determines the energy of the oscillation
Period
The period of harmonic motion denotes the time it takes for a complete cycle or oscillation to occur. In essence, it's how long it takes for the point to return to its starting position and start over. For the equation \( d = 6 \sin \frac{2\pi}{3} t \), the period \( T \) can be found using the formula \( T = \frac{2\pi}{\omega} \), where \( \omega \) represents the angular frequency. Substituting \( \omega = \frac{2\pi}{3} \), we find \( T = 3 \) seconds.
This means it takes 3 seconds for the point to complete one full oscillation. Understanding the period is crucial, as it gives insight into the speed of the harmonic motion.
This means it takes 3 seconds for the point to complete one full oscillation. Understanding the period is crucial, as it gives insight into the speed of the harmonic motion.
- Period \( T = 3 \) seconds
- Time for one complete cycle
- Influences the frequency
Frequency
Frequency is a measure of how often oscillations occur in a specific time frame, typically measured in hertz (Hz), which denotes cycles per second. It is the reciprocal of the period and can be calculated using the formula \( f = \frac{1}{T} \). For the given motion equation, since the period \( T \) is 3 seconds, the frequency \( f \) becomes \( \frac{1}{3} \) Hz.
Frequency provides a sense of urgency or repetition for the motion. In this context, it tells us that the point completes \( \frac{1}{3} \) of a cycle each second, which frames how quickly the harmonic motion repeats.
Frequency provides a sense of urgency or repetition for the motion. In this context, it tells us that the point completes \( \frac{1}{3} \) of a cycle each second, which frames how quickly the harmonic motion repeats.
- Frequency \( f = \frac{1}{3} \) Hz
- Number of cycles per second
- Determines how frequent the motion is
Sine Function
The sine function in the context of this harmonic motion controls the shape and pattern of the oscillation. It's a smooth periodic function that is critical to describing the motion under consideration. In the equation \( d = 6 \sin \frac{2\pi}{3} t \), the sine function means the motion will follow a sinusoidal path.
The properties of the sine function include:
The properties of the sine function include:
- Periodic behavior: Repeats over intervals of \( 2\pi \)
- Shape: Creates a smooth, wave-like oscillation
- Range: Values between -1 and 1, scaled by amplitude
Other exercises in this chapter
Problem 69
The strength of Earth's magnetic field varies with the depth below the surface. The strength at depth \(z\) and time \(t\) can sometimes be approximated using t
View solution Problem 69
Verify the identity by transforming the lefthand side into the right-hand side. $$\log \csc \theta=-\log \sin \theta$$
View solution Problem 70
Verify the identity by transforming the lefthand side into the right-hand side. $$\log \tan \theta=\log \sin \theta-\log \cos \theta$$
View solution Problem 71
A point \(P\) in simple harmonic motion has a period of \(3 \mathrm{sec}-\) onds and an amplitude of 5 centimeters. Express the motion of \(P\) by means of an e
View solution