Problem 70
Question
Describe how the formula is a transformation of a toolkit function. Then sketch a graph of the transformation. $$g(x)=5(x+3)^{2}-2$$
Step-by-Step Solution
Verified Answer
The function is a vertically stretched, horizontally translated, and vertically shifted quadratic.
1Step 1: Identify the Toolkit Function
The toolkit function for this transformation is the basic quadratic function, which is \( f(x) = x^2 \). Our goal is to understand how \( g(x) \) is a transformation of this function.
2Step 2: Locate the Horizontal Translation
In the function \( g(x) = 5(x+3)^2 - 2 \), the expression \((x+3)\) indicates a horizontal translation. This means the graph of the basic function \( f(x) = x^2 \) has been shifted to the left by 3 units.
3Step 3: Identify the Vertical Translation
The constant \(-2\) in the function \( g(x) = 5(x+3)^2 - 2 \) indicates a vertical translation. The whole graph is shifted downwards by 2 units.
4Step 4: Recognize the Vertical Stretch
The coefficient 5 in front of the \((x+3)^2\) term suggests a vertical stretch. This means the graph is stretched away from the x-axis by a factor of 5, making it steeper.
5Step 5: Combine the Transformations
Applying these transformations in sequence: first horizontally shift the graph of \( f(x) = x^2 \) left by 3 units, then stretch it vertically by a factor of 5, and finally shift it down by 2 units to complete the transformation to \( g(x) \).
6Step 6: Sketch the Transformed Graph
Now, sketch the graph based on transformations:- Start with the basic parabolic graph of \( f(x) = x^2 \).- Shift the vertex from (0,0) to (-3,0).- Stretch it vertically, making it narrower (as if you are pulling it upwards).- Move the vertex 2 units down to (-3, -2). The new graph has its vertex at (-3, -2), is narrow due to the stretch, and opens upwards.
Key Concepts
Quadratic FunctionHorizontal TranslationVertical TranslationVertical Stretch
Quadratic Function
A quadratic function is a type of polynomial function that can be written in the form \( f(x) = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. The simplest form of a quadratic function is the toolkit function \( f(x) = x^2 \), which is a parabola opening upwards with its vertex at the origin, (0,0).
Quadratic functions have many unique features:
Quadratic functions have many unique features:
- The graph is a symmetrical curve called a parabola.
- The vertex is the highest or lowest point, depending on the direction of the parabola.
- The axis of symmetry runs vertically through the vertex, often defined as \( x = -\frac{b}{2a} \) for the general quadratic equation.
- The parabola opens upwards if \( a > 0 \) and downwards if \( a < 0 \).
Horizontal Translation
A horizontal translation alters the location of a graph along the x-axis. For a quadratic function like \( g(x) = (x + 3)^2 \), the expression \( (x + 3) \) indicates a horizontal shift. Specifically,
To visualize this, consider the basic parabola \( f(x) = x^2 \):
- If we see \( (x + 3) \), it implies moving the graph left by 3 units.
- Conversely, \( (x - 3) \) would mean moving right by 3 units.
To visualize this, consider the basic parabola \( f(x) = x^2 \):
- Its vertex starts at (0,0).
- A horizontal translation moves the vertex along the x-axis.
Vertical Translation
Vertical translation refers to shifting the graph up or down along the y-axis. For the quadratic function \( g(x) = 5(x+3)^2 - 2 \), the term \(-2\) indicates a vertical translation.
Visualizing this, take the parabolic graph post-horizontal shift \( (-3,0) \):
- If the constant is negative, like \(-2\), the graph moves downward by that number of units.
- If the constant were positive, the graph would shift upward.
Visualizing this, take the parabolic graph post-horizontal shift \( (-3,0) \):
- Now, shift the entire graph down 2 units.
- This moves the vertex to the new point (-3, -2).
Vertical Stretch
A vertical stretch changes the steepness of a graph. It involves "stretching" the graph away from the x-axis, making it either taller or more compressed.For the function \( g(x) = 5(x+3)^2 - 2 \), the coefficient 5 signifies a vertical stretch.
To understand this practically:
- A value greater than 1 (like 5) implies the graph is stretched upwards, making it steeper.
- Conversely, a value less than 1 but greater than 0 (such as 0.5) would compress it, making the graph wider.
To understand this practically:
- The basic parabola \( f(x) = x^2 \) becomes steeper when multiplied by 5.
- This results in a "narrower" appearance because the sides of the parabola approach the y-axis more sharply.
Other exercises in this chapter
Problem 70
For the following exercises, use the function values for \(f\) and \(g\) shown in Table 4 to evaluate the expressions. $$\begin{array}{||cc|c|c|c|c|c|c|c|} \hli
View solution Problem 70
For the following exercises, describe how the formula is a transformation of a toolkit function. Then sketch a graph of the transformation. $$ g(x)=5(x+3)^{2}-2
View solution Problem 70
For the following exercises, evaluate the function \(f\) at the values \(f(-2), f(-1), f(0), f(1),\) and \(f(2)\). $$ f(x)=8 x^{2}-7 x+3 $$
View solution Problem 71
Use the function values for \(f\) and \(g\) shown in Table 4 to evaluate the expressions. $$ \begin{array}{|c|r|r|r|r|r|r|r|} \hline \boldsymbol{x} & -3 & -2 &
View solution