Problem 70
Question
Calculate the molar mass of each of the following compounds: (a) \(\mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{O}_{7}\right)_{2},\) iron (II) gluconate, a dietary supplement (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{SH},\) butanethiol, has a skunk-like odor (c) \(\mathrm{C}_{20} \mathrm{H}_{24} \mathrm{N}_{2} \mathrm{O}_{2},\) quinine, used as an antimalarial drug
Step-by-Step Solution
Verified Answer
(a) 446.14 g/mol; (b) 90.19 g/mol; (c) 324.42 g/mol.
1Step 1: Identify the Elements and Their Atomic Masses
For each compound, list each element present and note its atomic mass. Assume the atomic masses are as follows: Fe: 55.85 g/mol, C: 12.01 g/mol, H: 1.01 g/mol, O: 16.00 g/mol, S: 32.07 g/mol, N: 14.01 g/mol.
2Step 2: Write the Molecular Formula of Iron (II) Gluconate
The formula is \(\mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{O}_{7}\right)_{2}\). This indicates 1 iron atom, 12 carbon atoms, 22 hydrogen atoms, and 14 oxygen atoms in one formula unit.
3Step 3: Calculate the Molar Mass of Iron (II) Gluconate
Multiply the number of each type of atom by its atomic mass and sum them up: \[\text{Molar mass} = \left(2 \times 55.85\right) + \left(12 \times 12.01\right) + \left(22 \times 1.01\right) + \left(14 \times 16.00\right) = 446.14 \, \text{g/mol}.\]
4Step 4: Write the Molecular Formula of Butanethiol
The formula is \(\mathrm{C}_{4}\mathrm{H}_{10}\mathrm{S}\), indicating 4 carbon atoms, 10 hydrogen atoms, and 1 sulfur atom.
5Step 5: Calculate the Molar Mass of Butanethiol
Multiply the number of each type of atom by its atomic mass and sum them up: \[\text{Molar mass} = \left(4 \times 12.01\right) + \left(10 \times 1.01\right) + \left(1 \times 32.07\right) = 90.19 \, \text{g/mol}.\]
6Step 6: Write the Molecular Formula of Quinine
The formula is \(\mathrm{C}_{20} \mathrm{H}_{24} \mathrm{N}_{2} \mathrm{O}_{2}\), indicating 20 carbon atoms, 24 hydrogen atoms, 2 nitrogen atoms, and 2 oxygen atoms.
7Step 7: Calculate the Molar Mass of Quinine
Multiply the number of each type of atom by its atomic mass and sum them up: \[\text{Molar mass} = \left(20 \times 12.01\right) + \left(24 \times 1.01\right) + \left(2 \times 14.01\right) + \left(2 \times 16.00\right) = 324.42 \, \text{g/mol}.\]
Key Concepts
Molecular FormulaAtomic MassChemical CompoundsElemental Composition
Molecular Formula
A molecular formula is a representation of a chemical compound which indicates the actual number of each type of atom present in a molecule. It gives us a direct insight into the composition of the compound.
For example, in iron (II) gluconate, the molecular formula is \( \mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{O}_{7}\right)_{2}\). This formula tells us that in one formula unit, there are:
This initial step of identifying the molecular formula is crucial as it acts as the foundation for any further calculation or analysis.
For example, in iron (II) gluconate, the molecular formula is \( \mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{O}_{7}\right)_{2}\). This formula tells us that in one formula unit, there are:
- 1 iron atom,
- 12 carbon atoms,
- 22 hydrogen atoms,
- and 14 oxygen atoms.
This initial step of identifying the molecular formula is crucial as it acts as the foundation for any further calculation or analysis.
Atomic Mass
Atomic mass, typically expressed in grams per mole (g/mol), is the mass of an individual atom of an element. Recognizing the atomic mass of each element is vital in computations involving chemical compounds.
For example, in the problem at hand, we have the following atomic masses:
For example, in the problem at hand, we have the following atomic masses:
- Iron (Fe): 55.85 g/mol
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol
- Oxygen (O): 16.00 g/mol
- Sulfur (S): 32.07 g/mol
- Nitrogen (N): 14.01 g/mol
Chemical Compounds
Chemical compounds are substances formed from two or more elements chemically bonded together. They often have distinct physical and chemical properties compared to their individual elements.
Each compound has a unique molecular formula that shows its elemental composition and provides a roadmap for determining its characteristics, such as molar mass. In our examples:
Each compound has a unique molecular formula that shows its elemental composition and provides a roadmap for determining its characteristics, such as molar mass. In our examples:
- Iron (II) Gluconate: \( \mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{11} \mathrm{O}_{7}\right)_{2} \)
- Butanethiol: \( \mathrm{C}_{4}\mathrm{H}_{10}\mathrm{S} \)
- Quinine: \( \mathrm{C}_{20} \mathrm{H}_{24} \mathrm{N}_{2} \mathrm{O}_{2} \)
Elemental Composition
Elemental composition refers to the proportion of each element within a compound. Understanding this enables insights into the compound's structure and properties.
The elemental composition of a compound can be determined from its molecular formula. For example, in iron (II) gluconate:
This is essential for tailoring reactions and processes for desired outcomes, especially in fields such as pharmacology, where precise compound formulations are essential.
The elemental composition of a compound can be determined from its molecular formula. For example, in iron (II) gluconate:
- Each molecule contains 1 iron atom, which is a fundamental part of its structure.
- Carbon, hydrogen, and oxygen appear in higher quantities, influencing its properties and function.
This is essential for tailoring reactions and processes for desired outcomes, especially in fields such as pharmacology, where precise compound formulations are essential.
Other exercises in this chapter
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