Problem 70
Question
Animal propulsion. Squids and octopuses propel them- selves by expelling water. They do this by taking the water into a cavity and then suddenly contracting the cavity, forcing the water to shoot out of an opening. A 6.50 \(\mathrm{kg}\) squid (including the water in its cavity) that is at rest suddenly sees a dangerous predator. (a) If this squid has 1.75 \(\mathrm{kg}\) of water in its cavity, at what speed must it expel the water to suddenly achieve a speed of 2.50 \(\mathrm{m} / \mathrm{s}\) to escape the predator'? Neglect any drag effects of the surrounding water. (b) How much kinetic energy does the squid create for this escape maneuver?
Step-by-Step Solution
Verified Answer
(a) 6.79 m/s; (b) 55.15 J.
1Step 1: Understand the Problem
We have a 6.50 kg squid, including 1.75 kg of water in its cavity. Initially at rest, the squid must expel water to reach a speed of 2.50 m/s. We need to calculate the speed at which the squid must expel the water to achieve this and find the kinetic energy created for its escape.
2Step 2: Apply Conservation of Momentum
Since the squid is initially at rest, the system's total momentum is zero. By conservation of momentum, the momentum of the expelled water must equal the momentum gained by the squid:\[m_s \cdot v_s = m_w \cdot v_w\]where:\(m_s = 6.50 - 1.75 = 4.75 \) kg (mass of squid without water),\(v_s = 2.50\) m/s (velocity of squid), and\(m_w = 1.75\) kg (mass of water).We need to find \(v_w\), the velocity of the expelled water.
3Step 3: Solve for Velocity of Expelled Water
Rearrange the conservation of momentum equation to solve for \(v_w\):\[v_w = \frac{m_s \cdot v_s}{m_w}\]Substitute the values:\[v_w = \frac{4.75\, \text{kg} \times 2.50\, \text{m/s}}{1.75\, \text{kg}}\]\[v_w = 6.79\, \text{m/s}\]
4Step 4: Calculate Kinetic Energy of Squid
The kinetic energy \(KE\) of the squid is given by the formula:\[KE = \frac{1}{2} m_s v_s^2\]Substitute the known values:\[KE = \frac{1}{2} \times 4.75\, \text{kg} \times (2.50\, \text{m/s})^2\]\[KE = \frac{1}{2} \times 4.75 \times 6.25\, \text{J}\]\[KE = 14.84\, \text{J}\]
5Step 5: Calculate Total Kinetic Energy of Water
Similarly, calculate the kinetic energy of the expelled water:\[KE_w = \frac{1}{2} m_w v_w^2\]Substitute the values:\[KE_w = \frac{1}{2} \times 1.75\, \text{kg} \times (6.79\, \text{m/s})^2\]\[KE_w = \frac{1}{2} \times 1.75 \times 46.06\, \text{J}\]\[KE_w = 40.31\, \text{J}\]
6Step 6: Determine How Much Kinetic Energy the Squid Creates
Total kinetic energy is the sum of the kinetic energy of the squid and the expelled water:\[KE_{total} = KE + KE_w\]\[KE_{total} = 14.84\, \text{J} + 40.31\, \text{J}\]\[KE_{total} = 55.15\, \text{J}\]
Key Concepts
Kinetic Energy CalculationPropulsion MechanicsPhysics Problem Solving
Kinetic Energy Calculation
Kinetic energy is the energy that an object possesses due to its motion. Calculating kinetic energy involves understanding the relationship between mass and velocity. This concept plays a significant role in solving physics problems related to motion.In the context of our squid propulsion example, we calculated the kinetic energy that the squid generated during its escape maneuver. The formula to calculate kinetic energy is: \[ KE = \frac{1}{2} mv^2 \]where
- \( m \) is the mass of the moving object.
- \( v \) is the velocity of the object.
Propulsion Mechanics
Propulsion mechanics involves the study of forces that propel objects through different media. In this case, we are examining how a squid uses a jet propulsion mechanism to move rapidly through water, a common method seen in many aquatic creatures.
The squid's propulsion method relies on the conservation of momentum. The squid first fills a cavity with water and then expels it forcefully. When the squid expels water at a certain velocity, an equal and opposite reaction propels the squid in the opposite direction. This phenomenon is based on Newton's third law of motion.
Let's break it down:
- The squid's mass without the expelled water is 4.75 kg.
- The expelled mass of water is 1.75 kg.
- The squid escapes at a velocity of 2.50 m/s.
- The velocity of the expelled water must balance the momentum to zero since initially, the system (squid plus water) is at rest.
Physics Problem Solving
Solving physics problems often involves applying core principles like the conservation of momentum or energy equations to analyze and predict outcomes. To tackle physics problems efficiently, understanding the initial conditions and the laws governing the system is crucial.Our squid escape scenario is an excellent example of physics problem solving. Initially at rest, the momentum of the entire system must remain zero once the squid starts moving. The known values—a mass of 6.50 kg including water, a required speed of 2.50 m/s for escape, and a water mass of 1.75 kg—are key inputs.A structured approach involves:
- Identifying the goal, such as calculating velocity or energy.
- Applying appropriate formulas, such as momentum conservation \( m_s \cdot v_s = m_w \cdot v_w \).
- Substituting known values into these formulas.
- Calculating the unknowns step by step.
Other exercises in this chapter
Problem 68
\(\bullet\) A 5.00 g bullet traveling horizontally at 450 \(\mathrm{m} / \mathrm{s}\) is shot through a 1.00 kg wood block suspended on a string 2.00 \(\mathrm{
View solution Problem 69
\(\bullet\) Jonathan and Jane are sitting in a sleigh that is at rest on frictionless ice. Jonathan's weight is \(800 \mathrm{N},\) Jane's weight is \(600 \math
View solution Problem 74
Forensic science. Forensic scientists can measure the muzzle velocity of a gun by firing a bullet horizontally into a large hanging block that absorbs the bulle
View solution Problem 75
\(\bullet\) A 20.0 -kg lead sphere is hanging from a hook by a thin wire 3.50 m long, and is free to swing in a complete circle. Suddenly it is struck horizonta
View solution