Problem 70
Question
An electric dipole is placed at an angle of \(60^{\circ}\) with an electric field of intensity \(10^{5} \mathrm{NC}^{-1}\). It experiences a torque equal to \(8 \sqrt{3} \mathrm{~N}-\mathrm{m} .\) Calculate the charge on the dipole, if the dipole length is \(2 \mathrm{~cm}\). (a) \(-8 \times 10^{3} \mathrm{C}\) (b) \(8.54 \times 10^{-4} \mathrm{C}\) (c) \(8 \times 10^{-3} \mathrm{C}\) (d) \(0.85 \times 10^{-6} \mathrm{C}\)
Step-by-Step Solution
Verified Answer
The charge on the dipole is \(8 \times 10^{-3} \mathrm{C}\) (Option c).
1Step 1: Write down the formula for torque experienced by an electric dipole
The torque (τ) experienced by an electric dipole in a uniform electric field is given by the formula: \( \tau = pE \sin \theta \), where \( p \) is the dipole moment, \( E \) is the electric field intensity, and \( \theta \) is the angle between \( \vec{p} \) and \( \vec{E} \).
2Step 2: Set up the dipole moment relation
The dipole moment \( p \) is defined as \( p = q \cdot d \), where \( q \) is the charge on each dipole end and \( d \) is the separation distance between the charges (i.e., the dipole length). For this problem, \( d = 2 \, \text{cm} = 0.02 \text{ m} \).
3Step 3: Substitute known values into the torque formula
We are given \( \tau = 8 \sqrt{3} \text{ Nm} \), \( E = 10^{5} \text{ Nm/C} \), and \( \theta = 60^{\circ} \). Substitute into the torque formula: \[ 8 \sqrt{3} = q \cdot 0.02 \cdot 10^{5} \cdot \sin 60^{\circ} \].
4Step 4: Calculate \( \sin 60^{\circ} \)
The value of \( \sin 60^{\circ} \) is \( \frac{\sqrt{3}}{2} \). Substitute this value into the equation from Step 3.
5Step 5: Solve for the charge \( q \)
Substitute \( \sin 60^{\circ} = \frac{\sqrt{3}}{2} \) into the equation: \[ 8 \sqrt{3} = q \cdot 0.02 \cdot 10^{5} \cdot \frac{\sqrt{3}}{2} \]. Simplify to obtain: \[ 8 \sqrt{3} = q \cdot 1000 \cdot \frac{\sqrt{3}}{2} \]. Divide both sides by \( 500 \sqrt{3} \) to get: \[ q = \frac{8 \sqrt{3}}{500 \sqrt{3}} = \frac{8}{500} = 0.016 \text{ C} = 8 \times 10^{-3} \text{ C} \].
6Step 6: Compare the result with the options and select the correct answer
The calculated charge is \( 8 \times 10^{-3} \text{ C} \), which corresponds to option (c) in the given choices.
Key Concepts
Torque on DipoleElectric Field IntensityDipole Moment
Torque on Dipole
When an electric dipole is placed in an electric field, it experiences a torque that tends to rotate it. This torque is a result of the forces exerted by the electric field on the positive and negative charges in the dipole. Depending on the alignment, the torque may try to align the dipole with the electric field. The formula to calculate this torque is given by:\[\tau = pE \sin \theta\]where:
- \( \tau \) is the torque experienced by the dipole.
- \( p \) is the dipole moment, which indicates the strength of the dipole.
- \( E \) is the intensity of the electric field.
- \( \theta \) is the angle between the dipole moment vector \( \vec{p} \) and the electric field vector \( \vec{E} \).
Electric Field Intensity
The electric field intensity \( E \) is a measure of the strength of an electric field at a particular location. It is defined as the force experienced per unit positive charge placed at that point. The electric field intensity is expressed in the formula:\[E = \frac{F}{q_0}\]where:
- \( E \) is the electric field intensity.
- \( F \) represents the force experienced by a small positive test charge.
- \( q_0 \) is the magnitude of the test charge.
Dipole Moment
A dipole moment is a quantitative measure of the dipole strength. It's a vector quantity that points from the negative charge to the positive charge in a dipole. The magnitude of the dipole moment is calculated as:\[p = q \cdot d\]where:
- \( p \) is the dipole moment.
- \( q \) is the magnitude of the charge at each end of the dipole.
- \( d \) is the distance separating the charges, also known as the dipole length.
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