Problem 7
Question
Write the trigonometric expression in terms of sine and cosine, and then simplify. $$\tan ^{2} x-\sec ^{2} x$$
Step-by-Step Solution
Verified Answer
The expression simplifies to \(-1\).
1Step 1: Express in Terms of Sine and Cosine
Start by expressing \( \tan x \) and \( \sec x \) in terms of sine and cosine:\[ \tan x = \frac{\sin x}{\cos x} \quad \text{and} \quad \sec x = \frac{1}{\cos x} \]These identities will help us rewrite the given expression.
2Step 2: Substitute and Expand
Substitute the identities for \( \tan x \) and \( \sec x \) into the expression \( \tan ^{2} x-\sec ^{2} x \):\[\left( \frac{\sin x}{\cos x} \right)^2 - \left( \frac{1}{\cos x} \right)^2 \]Simplify each term:\[\frac{\sin^2 x}{\cos^2 x} - \frac{1}{\cos^2 x} \]
3Step 3: Combine Fractions
Since both terms have the same denominator, combine them:\[\frac{\sin^2 x - 1}{\cos^2 x} \]
4Step 4: Use Pythagorean Identity
Recall the Pythagorean identity: \( \sin^2 x + \cos^2 x = 1 \). Rearrange it to express \( 1 - \sin^2 x \) as \( \cos^2 x \):\[ 1 - \sin^2 x = \cos^2 x \]Use this to rewrite \( \sin^2 x - 1 \) as:\[ -(1 - \sin^2 x) = -\cos^2 x \]
5Step 5: Simplify the Expression
Substitute \( -\cos^2 x \) into the combined fraction:\[\frac{-\cos^2 x}{\cos^2 x} \]Simplify it to:\[ -1 \]The expression simplifies to \( -1 \).
Key Concepts
Sine FunctionCosine FunctionPythagorean Identity
Sine Function
The sine function is a fundamental component of trigonometry, often abbreviated as "sin." It is a periodic function that represents the y-coordinate position on the unit circle. The function is defined for an angle \( x \) and is written as \( \sin x \). This function helps in understanding various trigonometric identities and is essential in expressing other trigonometric functions such as tangent. The sine function oscillates between -1 and 1, which means it never exceeds these values.
- Defined as \( \sin x = \frac{\text{opposite side}}{\text{hypotenuse}} \) in a right triangle.
- Periodicity: \( \sin(x + 2\pi) = \sin x \).
- Symmetry: \( \sin(-x) = -\sin x \).
Cosine Function
The cosine function, denoted as "cos," is another crucial trigonometric function. It measures the x-coordinate on the unit circle for a given angle \( x \), complementing the sine function by defining its relationship through the right triangle. The cosine function is equally periodic and its values range from -1 to 1, similar to the sine function. It is expressed as \( \cos x \) and is often used alongside the sine function to express other trigonometric identities.
- Defined as \( \cos x = \frac{\text{adjacent side}}{\text{hypotenuse}} \) in a right triangle.
- Periodicity: \( \cos(x + 2\pi) = \cos x \).
- Symmetry: \( \cos(-x) = \cos x \).
Pythagorean Identity
One of the most important and widely used identities in trigonometry is the Pythagorean identity. It is expressed as \( \sin^2 x + \cos^2 x = 1 \). This identity forms the foundation for many mathematical simplifications, as it establishes the fundamental relationship between the square of the sine and cosine functions. This identity can be rearranged to solve for any one of the functions in terms of the other, such as \( \cos^2 x = 1 - \sin^2 x \) or \( \sin^2 x = 1 - \cos^2 x \).
- Derived from the Pythagorean theorem in geometry.
- Helps in simplifying expressions by converting square terms.
- Assists in converting different trigonometric forms within identities.
Other exercises in this chapter
Problem 7
Solve the given equation. $$2 \sin 2 \theta-3 \sin \theta=0$$
View solution Problem 7
Use an Addition or Subtraction Formula to find the exact value of the expression, as demonstrated in Example 1. $$\tan 15^{\circ}$$
View solution Problem 8
Solve the given equation. $$\cos \theta=\frac{\sqrt{3}}{2}$$
View solution Problem 8
Find \(\sin 2 x, \cos 2 x,\) and \(\tan 2 x\) from the given information. \(\sec x=2, \quad x\) in Quadrant IV
View solution