Problem 7
Question
Write the point-slope equation of the line determined by the given data. Slope \(-1,\) point \((-\sqrt{2}, 0)\)
Step-by-Step Solution
Verified Answer
The point-slope equation is \( y = -x - \sqrt{2} \).
1Step 1: Identify the Formula
The point-slope form equation of a line can be written as \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \((x_1, y_1)\) is a point on the line.
2Step 2: Substitute Given Values
We substitute the given values into the point-slope formula. Here, the slope \( m \) is \(-1\), and the point \((x_1, y_1)\) is \((-\sqrt{2}, 0)\). The equation becomes \( y - 0 = -1(x - (-\sqrt{2})) \).
3Step 3: Simplify the Equation
Simplify the equation by multiplying and distributing the slope: \( y = -1(x + \sqrt{2}) \). This expands to \( y = -x - \sqrt{2} \), which is the point-slope form of the equation.
Key Concepts
Equation of a LineSlopeSubstitution Method
Equation of a Line
A line can be represented by various equations, but one of the most insightful is the point-slope form. This equation of a line is valuable for understanding how a line behaves just by knowing one of its points and the slope. The point-slope form is written as:
- \( y - y_1 = m(x - x_1) \)
- \( m \) represents the slope of the line.
- The point \((x_1, y_1) \) is any specific point on the line.
Slope
The slope of a line is a key concept in understanding linear equations and their graphs. It measures how steep a line is and is defined as the ratio of vertical change (rise) to horizontal change (run) between two points on the line. The formula to calculate the slope \( m \) is:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \)
- A positive slope means the line goes upwards as you move from left to right.
- A negative slope, like in the given exercise example, means the line descends as you go from left to right.
- A zero slope indicates a horizontal line.
- An undefined slope means a vertical line.
- -1, signifying a line descending at a 45-degree angle relative to the axes.
Substitution Method
The substitution method is a straightforward approach often used to find specific values or to insert known values into equations. In the context of linear equations, it's particularly useful for customizing general equations to fit specific situations.Here's how the substitution method works in our exercise:
- Identify the values given: the slope \( m = -1 \) and the point \( (x_1, y_1) = (-\sqrt{2}, 0) \).
- Substitute these values into the point-slope formula \( y - y_1 = m(x - x_1) \).
- Replace \( y_1 \) with 0, \( m \) with -1, and \( x_1 \) with \(-\sqrt{2} \), modifying the equation accordingly.
- After substitution, simplify the equation as necessary. For our example, this results in \( y = -x - \sqrt{2} \).
Other exercises in this chapter
Problem 6
Convert the decimal to a rational fraction. (Ellipses are included in some exercises to indicate repetition.) \(15.7231231231 \ldots\)
View solution Problem 7
Calculate the given expression without using a calculator. \(\cos (\pi / 6)+\cos (\pi / 3)\)
View solution Problem 7
State the domain of the function defined by the given expression. $$ \sqrt{x^{2}-4 x+5} $$
View solution Problem 7
The Cartesian equation of a circle is given. Sketch the circle and specify its center and radius. \((x-1)^{2}+(y-3)^{2}=9\)
View solution