Problem 7
Question
Write the augmented matrix for each system. Do not solve the system. $$\begin{array}{r} 2 x+3 y=11 \\ x+2 y=8 \end{array}$$
Step-by-Step Solution
Verified Answer
The augmented matrix is \(\begin{bmatrix} 2 & 3 & | & 11 \\ 1 & 2 & | & 8 \end{bmatrix}\).
1Step 1: Understand the System of Equations
First, we have a system of linear equations consisting of two equations. The system is: \(2x + 3y = 11\) and \(x + 2y = 8\). Each equation represents a line in a 2-dimensional space.
2Step 2: Identify Coefficients and Constants
Next, we identify the coefficients of the variables and the constants from each equation. From equation 1: \(2x + 3y = 11\), the coefficients are \(2\) for \(x\), \(3\) for \(y\), and the constant is \(11\). For equation 2: \(x + 2y = 8\), the coefficients are \(1\) for \(x\), \(2\) for \(y\), and the constant is \(8\).
3Step 3: Construct the Augmented Matrix
An augmented matrix is a compact way to represent a system of linear equations. It consists of the coefficients of the variables and the constants from the equations systematically arranged. For the given system, the augmented matrix is constructed as \[ \begin{bmatrix} 2 & 3 & | & 11 \ 1 & 2 & | & 8 \end{bmatrix} \]. Here, each row corresponds to an equation, and the vertical line separates the coefficients and the constants.
Key Concepts
Understanding the System of EquationsExploring Linear EquationsIdentifying Coefficients and Constants
Understanding the System of Equations
A system of equations is a set of two or more equations that share two or more variables. These equations are considered simultaneously because they describe relationships where the same variables are involved. For instance, consider the system:
Systems can be solved using various methods, such as substitution, elimination, or by using matrices. In our context, we focus on representing the system with an augmented matrix, which serves as an efficient way to handle and manipulate these equations.
- \(2x + 3y = 11\)
- \(x + 2y = 8\)
Systems can be solved using various methods, such as substitution, elimination, or by using matrices. In our context, we focus on representing the system with an augmented matrix, which serves as an efficient way to handle and manipulate these equations.
Exploring Linear Equations
Linear equations are equations where the highest power of the variable is one. They form straight lines when graphed on the coordinate plane. The general form of a linear equation in two variables is \(ax + by = c\), where \(a\), \(b\), and \(c\) are constants, and \(x\) and \(y\) are variables.
In our given system:
In our given system:
- The first equation is \(2x + 3y = 11\), with "2x" and "3y" forming a linear combination resulting in the constant 11.
- The second equation is \(x + 2y = 8\), following the same linear pattern with a different set of coefficients and constant.
Identifying Coefficients and Constants
In the context of linear equations and systems, coefficients and constants play crucial roles. The **coefficients** are the numbers that multiply the variables (like \(x\) and \(y\)), while the **constants** are the standalone numbers. Let's break it down with our example.
- For the equation \(2x + 3y = 11\):
- The coefficient of \(x\) is 2.
- The coefficient of \(y\) is 3.
- The constant is 11.
- For the equation \(x + 2y = 8\):
- The coefficient of \(x\) is 1 (often implied).
- The coefficient of \(y\) is 2.
- The constant is 8.
Other exercises in this chapter
Problem 7
Find the partial fraction decomposition for each rational expression. $$\frac{5}{3 x(2 x+1)}$$
View solution Problem 7
Determine whether A and B are imerses by calculating AB and BA. Do not use a calculator. $$A=\left[\begin{array}{rrr} -1 & -1 & -1 \\ 4 & 5 & 0 \\ 0 & 1 & -3 \e
View solution Problem 7
Find the dimension of each matrix. Identify any square, column, or rove matrices. Do not use a calculator. $$[-9]$$
View solution Problem 7
Solve each system analytically. If the equations are dependent, write the solution set in terms of the variable \(z\). $$\begin{aligned} x+y+z &=5 \\ y+z &=2 \\
View solution