Problem 7
Question
Use the quadratic formula to solve each equation. These equations have real number solutions only. $$ x^{2}+7 x+4=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{-7 + \sqrt{33}}{2}\) and \(x = \frac{-7 - \sqrt{33}}{2}\).
1Step 1: Identify coefficients
In the quadratic equation \(ax^2 + bx + c = 0\), identify the coefficients \(a\), \(b\), and \(c\). For the equation \(x^2 + 7x + 4 = 0\), we have \(a = 1\), \(b = 7\), and \(c = 4\).
2Step 2: Set up the quadratic formula
The quadratic formula is \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\). We will substitute \(a = 1\), \(b = 7\), and \(c = 4\) into this formula.
3Step 3: Calculate the discriminant
Calculate the discriminant \(b^2 - 4ac\). This is \(7^2 - 4 \cdot 1 \cdot 4 = 49 - 16 = 33\).
4Step 4: Plug values into the quadratic formula
Substitute the values \(b = 7\), \(a = 1\), and the discriminant \(33\) into the formula: \(x = \frac{-7 \pm \sqrt{33}}{2 \cdot 1}\).
5Step 5: Simplify the solution
Simplify the expression to solve for \(x\): \(x = \frac{-7 + \sqrt{33}}{2}\) and \(x = \frac{-7 - \sqrt{33}}{2}\). Thus, the solutions are \(x = \frac{-7 + \sqrt{33}}{2}\) and \(x = \frac{-7 - \sqrt{33}}{2}\).
Key Concepts
DiscriminantReal NumbersQuadratic Equation
Discriminant
The discriminant is a key concept in solving quadratic equations. It comes from the quadratic formula, which is: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \).
Here, the term under the square root, \( b^2 - 4ac \), is the discriminant. The value of the discriminant can tell us important information about the types of solutions the quadratic equation will have.
Here, the term under the square root, \( b^2 - 4ac \), is the discriminant. The value of the discriminant can tell us important information about the types of solutions the quadratic equation will have.
- If the discriminant is positive, as in our equation, the quadratic equation has two distinct real number solutions.
- If it is zero, the quadratic equation has exactly one real number solution, which is sometimes called a repeated or double root.
- If it is negative, there are no real number solutions, and the solutions are complex numbers.
Real Numbers
Real numbers are an integral part of mathematical concepts and equations. When we talk about real number solutions, we are referring to solutions that are not imaginary and can be located on the number line. An equation like the one we solved,\( x^2 + 7x + 4 = 0 \), has solutions in terms of real numbers because its discriminant was positive.
Real numbers include:
Real numbers include:
- All positive numbers (like 1, 2, 3.5, etc.).
- All negative numbers (like -1, -2.7, etc.).
- Zero.
Quadratic Equation
A quadratic equation is a second-degree polynomial equation of the form \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) represent coefficients, with \( a eq 0 \) to ensure it remains a quadratic.
All quadratic equations can potentially be solved using the quadratic formula. Our focus equation, \( x^2 + 7x + 4 = 0 \), is a classic example.
Quadratic equations can have:
All quadratic equations can potentially be solved using the quadratic formula. Our focus equation, \( x^2 + 7x + 4 = 0 \), is a classic example.
Quadratic equations can have:
- Two solutions.
- One solution (when there is a double root).
- Or no real solutions (when the roots are complex).
Other exercises in this chapter
Problem 6
Use the square root property to solve each equation. $$ y^{2}=20 $$
View solution Problem 6
Graph each quadratic function. Label the vertex and sketch and label the axis of symmetry. \(h(x)=x^{2}-4\)
View solution Problem 7
Write the solution set in interval notation. $$ 3 x^{2}+16 x
View solution Problem 7
Solve. See Example 2. $$ \frac{2}{x}+\frac{3}{x-1}=1 $$
View solution